Stoichiometry applied to reactions and chemical equations

AI Thread Summary
To solve the stoichiometry problem involving the reaction of aluminum hydroxide and sulfuric acid, first balance the equation: 2Al(OH)3 + 3H2SO4 → Al2(SO4)3 + 6H2O. Identify the limiting reactant by calculating the moles of both aluminum hydroxide and sulfuric acid, determining which produces the least amount of water. Use the mole-to-mole ratios from the balanced equation to find the moles of water produced by each reactant. Once the limiting reactant is established, convert the moles of water to mass to find the final answer. Understanding these steps is crucial for solving similar stoichiometry problems.
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Homework Statement


I don't understand this problem, i think he wants me to find the limeted reaction. If you could explain as good as possible. Thanks :smile:

Homework Equations


Al(OH)3(s) + H2SO4(l) → Al2(SO4)3(aq) + H2O(l)
If 1.28 g of aluminum hydroxide reacts with 3.73 g of sulfuric acid, what is the mass of the water produced? (Hint: First balance the equation, then think about limiting reactants.)

The Attempt at a Solution


I already balanced the equation, but don't know how to start the formula
2Al(OH)3(s) + 3H2SO4(l) → Al2(SO4)3(aq) + 6H2O(l)
 
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What is the limiting reactant, namely, the least moles of substance you have on the left?

How many moles of aluminum hydroxide do you have, and how many moles of sulfuric acid you have?

From there, perform your stoich, I assume you've been taught.
 
We just started this today. I didn't really understand it in class and didn't have enough time to ask the teacher. If you have any websites or a good book that walks me through these kinds of problems, i would appreciate it very much.
 
Well, first you need to find which reactant (aluminum hydroxide or sulfuric acid) produces the least amount of water. This is the limiting reagent.

To do this, use your mol to mol ratios. Have you done that in class yet? Find mols of aluminum hydroxide. Then, using mol to mol ratio, find how many mols of water would be produced from that amount of aluminum hydroxide.

Now find mols of sulfuric acid, and find the mols of water the same way as above.

Which produces the least amount of water? That is going to be your limiting reagent. Once the limiting reagent is used up, the reaction can't continue, right?

Now convert the mols of water to mass of water. Use the mols of water from the limiting reagent you found above.

I hope this makes sense, write back, I will try to explain more clearly.
 
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