How Much Lead(II) Sulfide Is Produced from 146.0 Grams of Ammonium Sulfide?

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To determine the grams of Lead(II) Sulfide produced from 146.0 grams of ammonium sulfide, the balanced chemical equation is essential: 2NH4S + Pb(NO3)2 → 2PbS + 2NH4NO3. The discussion emphasizes the importance of balancing the equation correctly to find the mole ratios. Once the equation is balanced, the next step involves calculating the molar masses and applying stoichiometry to convert grams of ammonium sulfide to grams of Lead(II) Sulfide. Understanding these concepts will lead to the correct answer for the problem.
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stoichiometry. Please help . Thanks!

1. how many grams of Lead(II) Sulfide will result from the combination of 146.0 grams of ammonium sulfide and excess Lead (II) Nitrate



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3. ooohhhkkaayyy .
I cannot even balance the equationn... sooo
this is what i have
2NH4S + Pb (NO3)2 -----> 2PbS + 2NH4 NO3
I CANNOT FIGURE THIS OUT TO SAVE MY LIFEEE
 
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If you understood the FeS problem from your other post (in which you gave a mostly reasonable solution and which was checked and improvement comments responded) then this one is the same idea. Look for the mole ratios from the written reaction, be sure to balance that reaction first; then use formula weights as needed according to the mole ratios.
 
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