How Do I Apply Stolz-Cesaro Theorem to Find the Limit of a Sequence?

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Homework Statement


hello, i have to find the limit of the next array

(xn)=(cos (π/n+1) + cos (π/n+2) + ...+ cos ( π/2n))/n
when n goes to infinity.

Homework Equations


I was told to apply stolz cesaro and that is where i ended up :
the limit is :

limit of cos ( π/2n+1) + cos (π/2n+2) -cos (π/n+1)

The Attempt at a Solution


How i finish this ?
 
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LazuRazvan said:

Homework Statement


hello, i have to find the limit of the next array

(xn)=(cos (π/n+1) + cos (π/n+2) + ...+ cos ( π/2n))/n
What you wrote in the first term was ##\cos(\frac{\pi}{n} + 1)##, and similar in the other two terms. Is that what you intended?
LazuRazvan said:
when n goes to infinity.

Homework Equations


I was told to apply stolz cesaro and that is where i ended up :
the limit is :

limit of cos ( π/2n+1) + cos (π/2n+2) -cos (π/n+1)
Same comment as above.

Also, to apply Stolz-Cesaro (https://en.wikipedia.org/wiki/Stolz–Cesàro_theorem), you need to use it with another sequence. What's the other sequence you are using?
LazuRazvan said:

The Attempt at a Solution


How i finish this ?
 
Last edited:
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
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