Strength of Electric Field with a point charge

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SUMMARY

The strength of the electric field generated by a point charge of +11 nC located at the origin can be calculated using the formula E = k|q|/r², where k is Coulomb's constant (approximately 8.99 x 10^9 N m²/C²). For the position (-5 cm, 5 cm), the distance r from the charge to the point is calculated using the Pythagorean theorem, resulting in r = √((-5)² + (5)²) = √50 cm. The electric field components along the x and y axes can be determined separately, and the resultant electric field is found by combining these components using the formula E_total = √(E_x² + E_y²).

PREREQUISITES
  • Understanding of Coulomb's Law
  • Familiarity with electric field concepts
  • Knowledge of vector addition
  • Basic proficiency in using the Pythagorean theorem
NEXT STEPS
  • Study the application of Coulomb's Law in different configurations of point charges
  • Learn about electric field lines and their representation
  • Explore the concept of superposition in electric fields
  • Investigate the effects of multiple charges on electric field strength
USEFUL FOR

Students in physics, electrical engineers, and anyone interested in understanding electric fields generated by point charges.

ltruiz45
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Problem:
A +11 nC charge is located at the origin.

Question:
What is the strength of the electric field at the position x,y (-5cm, 5cm) ?


I would think you would do this but when I try it I get the wrong answer

for x-axis - E=k|q|/r2
For y-axis - E=k|q|/r2

Then [itex]\sqrt{}Ex^2 + Ey^2[/itex]
 
Last edited:
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ltruiz45 said:
Problem:
A 11 charge is located at the origin.
What is "a 11 charge"?
Question:
What is the strength of the electric field at the position ?
At what position?

I would think you would do this but when I try it I get the wrong answer

for x-axis - E=k|q|/r2
For y-axis - E=k|q|/r2

Then [itex]\sqrt{}Ex^2 + Ey^2[/itex]
 

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