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Strength of materials (shear and moment)

  1. Jul 18, 2011 #1
    R at B = 5.0625
    R at A = 8.5kN-5.0625kN=3.4375kN

    x/0.9375=(0.5-x)/4.5625

    x=15/176

    but moment near x there i get different from both side:
    from A = 2.431kNm
    from B = 2.346kNm

    is there something wrong?
     

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    Last edited: Jul 18, 2011
  2. jcsd
  3. Jul 18, 2011 #2

    SteamKing

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    Your shear curve is not drawn correctly. For example, starting at A, the reaction gives a shear of 3.4375 kN. The distributed load between A and C is 1 kN/m over a distance of
    0.5 m. At C, there should be a jump discontinuity in the shear. Approaching from the left, the shear is 3.4375 - 0.5 * 1 = 2.9375 kN. The 2 kN concentrated load is applied at point C only. The shear value at C approaching from the right is 0.9375 kN. A similar situation will occur at point E with the 5 kN concentrated load there.

    In other words, your shear diagram is incorrect because you have incorporated the concentrated loads as if they were distributed loads.
     
  4. Jul 19, 2011 #3
    Oh I didnt see that. Thank you so much... :D
     
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