# Homework Help: Strength of materials (shear and moment)

1. Jul 18, 2011

### defdek

R at B = 5.0625
R at A = 8.5kN-5.0625kN=3.4375kN

x/0.9375=(0.5-x)/4.5625

x=15/176

but moment near x there i get different from both side:
from A = 2.431kNm
from B = 2.346kNm

is there something wrong?

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Last edited: Jul 18, 2011
2. Jul 18, 2011

### SteamKing

Staff Emeritus
Your shear curve is not drawn correctly. For example, starting at A, the reaction gives a shear of 3.4375 kN. The distributed load between A and C is 1 kN/m over a distance of
0.5 m. At C, there should be a jump discontinuity in the shear. Approaching from the left, the shear is 3.4375 - 0.5 * 1 = 2.9375 kN. The 2 kN concentrated load is applied at point C only. The shear value at C approaching from the right is 0.9375 kN. A similar situation will occur at point E with the 5 kN concentrated load there.

In other words, your shear diagram is incorrect because you have incorporated the concentrated loads as if they were distributed loads.

3. Jul 19, 2011

### defdek

Oh I didnt see that. Thank you so much... :D