Stress Strain Curve: Explaining Beyond UTS

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The discussion focuses on the behavior of materials beyond the ultimate tensile stress (UTS) in terms of stress and strain. Participants clarify that beyond UTS, the stress required to produce additional strain decreases significantly, indicating a rapid reduction in the material's ability to withstand stress. The concept of stiffness is debated, with emphasis on the fact that it primarily relates to the linear portion of the stress-strain curve. The conversation highlights the importance of understanding the diminishing stress levels needed for increased strain after reaching peak stress. Overall, the key takeaway is that beyond UTS, materials exhibit a rapid decline in stress resistance as strain increases.
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Homework Statement



Explain in terms of stress and strain what happens to the stretched material beyond the ultimate tensile stress.

Homework Equations


A curve similar to this


The Attempt at a Solution


I can see that the curve beyond UTS represents increasing stiffness but i can't really explain why or relate this to strain.( Does the zero gradient at uts mean zero stiffness ?)
 

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Nemo's said:
I can see that the curve beyond UTS represents increasing stiffness
Decreasing (and negative)?
but i can't really explain why or relate this to strain.( Does the zero gradient at uts mean zero stiffness ?)
Yes. Stiffness would be the slope, no?
But the question doesn't mention stiffness. It just asks you to discuss what's happening to the sample in terms of stress and strain.
 
But the question doesn't mention stiffness. It just asks you to discuss what's happening to the sample in terms of stress and strain.
So Can I just say that as the strain increases the stress decreases at an increasing rate?
I thought I had to mention the quantity represented by the slope in these curve-related questions.
I only said stiffness because I know that the Young Modulus is only related to the linear part of the curve.( Honestly I don't know which name to give the slope in this part)
 
Nemo's said:
So Can I just say that as the strain increases the stress decreases at an increasing rate?
Not sure that makes physical sense. Think of the test set-up. You, the experimenter, supply the stress. The test sample cannot control the stress on it. I would say that beyond the tensile strength (i.e. the peak stress) the stress level required to increase the strain diminishes increasingly rapidly.
I thought I had to mention the quantity represented by the slope in these curve-related questions.
I only said stiffness because I know that the Young Modulus is only related to the linear part of the curve.( Honestly I don't know which name to give the slope in this part)

From what I read, referring to stiffness does not solve that. That also refers to elastic deformation. This link is useful: http://www.etomica.org/app/modules/sites/MaterialFracture/Background1.html
 
haruspex said:
I would say that beyond the tensile strength (i.e. the peak stress) the stress level required to increase the strain diminishes increasingly rapidly.
Yes this makes a lot more sense.
Thanks a lot :)
 
haruspex said:
I would say that beyond the tensile strength (i.e. the peak stress) the stress level required to increase the strain diminishes increasingly rapidly.
Yes this makes a lot more sense.
Thanks a lot :)
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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