Stripping a neutron from an atom

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How do you strip a neutron from a particle? Thanks
 
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Neutrino98 said:
How do you strip a neutron from a particle? Thanks
Well, a neutron is considered a particle. A proton, deuteron, triton, or He nucleus (alpha particle) are considered particles.

What particle did on have in mind?

Neutrons can be removed from nuclei by interaction with gamma ray of appropriate energy. If a gamma ray of energy > ~2.22 MeV interacts with deuteron, the neutron and proton may part in a reaction known a photodissociation. Otherwise, if a sufficiently energetic gamma photon cause a neutron to be ejected from a nucleus, the reaction is termed 'photo-emission'.

Some fusion reactions also release neutrons, e.g., d+t => α + n, or d+d => He-3 + n (~50%).

Some nuclear reactions may result in the release of neutrons, e.g., a highly energetic proton or neutron can knock a neutron out of an atom. The reaction is term spallation.
 
A common portable laboratory source of neutrons is a mixture of an alpha emitter and beryllium: a fine powder mixture of plutonium and beryllium (PuBe) or americium and beryllium (AmBe). The absolute yield is in the range of 50 neutrons per million alphas. See http://prola.aps.org/abstract/PR/v98/i3/p740_1
 
thanks
 
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I'm following this paper by Kitaev on SL(2,R) representations and I'm having a problem in the normalization of the continuous eigenfunctions (eqs. (67)-(70)), which satisfy \langle f_s | f_{s'} \rangle = \int_{0}^{1} \frac{2}{(1-u)^2} f_s(u)^* f_{s'}(u) \, du. \tag{67} The singular contribution of the integral arises at the endpoint u=1 of the integral, and in the limit u \to 1, the function f_s(u) takes on the form f_s(u) \approx a_s (1-u)^{1/2 + i s} + a_s^* (1-u)^{1/2 - i s}. \tag{70}...
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