Stuck on find the frequncey and max speed of a wave, urnt

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Homework Help Overview

The discussion revolves around a transverse wave described by the equation y = 6.1 sin(0.010x + 3.0t). Participants are tasked with determining various properties of the wave, including frequency, speed, and maximum transverse speed, while also discussing the direction of propagation.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the relationship between wave properties and the equation parameters, with some attempting to derive frequency from angular frequency and period. Questions arise regarding the method to determine the direction of wave propagation and the calculation of maximum speed.

Discussion Status

Some guidance has been provided regarding the calculation of angular frequency and the method to find maximum speed. Multiple interpretations of wavelength have been explored, with participants questioning the initial assumption of its value.

Contextual Notes

There is a noted discrepancy in the wavelength calculation, with participants highlighting the importance of the wave number and the factor of pi in determining the correct wavelength.

mr_coffee
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Hello everyone! I got some parts of this question right but are stuck on others. Here is the problem:
The equation of a transverse wave traveling along a very long string is given by y = 6.1 sin(0.010x + 3.0t), where x and y are expressed in centimeters and t is in seconds. Determine the following values.

(a) the amplitude
6.1
(b) the wavelength
200
(c) the frequency
?
(d) the speed
?cm/s
(e) the direction of propagation of the wave
+x
[-x]
+y
-y

(f) the maximum transverse speed of a particle in the string
cm/s

From the equation i got the amplitude, From the wave # i got the wave length.
K = wave #
K = 2*pi/WaveLength
WaveLength=200

but now I'm stuck on how I'm suppose to find the frequency?
If i could find the period, i could find the frequency. or if i could find the angular frequency I also could find the frequnecy. Once I find frequency, finding speed would be easy. V = WaveLength*frequncey

How do you know the propagation of the wave? I got it right but it was through guessing.
-x was the answer.


Also how would i find the max speed? Does it invovle me taking the derivative of the function?

Thanks!
 
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mr_coffee said:
Hello everyone! I got some parts of this question right but are stuck on others. Here is the problem:
The equation of a transverse wave traveling along a very long string is given by y = 6.1 sin(0.010x + 3.0t), where x and y are expressed in centimeters and t is in seconds. Determine the following values.

(a) the amplitude
6.1
(b) the wavelength
200
(c) the frequency
?
(d) the speed
?cm/s
(e) the direction of propagation of the wave
+x
[-x]
+y
-y

(f) the maximum transverse speed of a particle in the string
cm/s

From the equation i got the amplitude, From the wave # i got the wave length.
K = wave #
K = 2*pi/WaveLength
WaveLength=200

but now I'm stuck on how I'm suppose to find the frequency?
If i could find the period, i could find the frequency. or if i could find the angular frequency I also could find the frequnecy. Once I find frequency, finding speed would be easy. V = WaveLength*frequncey

How do you know the propagation of the wave? I got it right but it was through guessing.
-x was the answer.


Also how would i find the max speed? Does it invovle me taking the derivative of the function?

Thanks!

The angular frequency [itex]\omega[/itex] is simply what multiplies the time ! (so 3.0).

A traveling wave moves to the right if the x and t terms have opposite signs.

You could find the velocity by taking the derivative with respect to time and then find when the velocity is max, but the quick answer is that the max speed of a particle is [itex]A \omega[/itex]

Patrick
 
THanks a lot man! WOrked perfectly!
 
What makes you think that the wavelength is 200 [cm?]?
k is the quantity that multiplies x , so wavelength = 2 pi /.01 = 628.
 
lightgrav said:
What makes you think that the wavelength is 200 [cm?]?
k is the quantity that multiplies x , so wavelength = 2 pi /.01 = 628.

Good point, lightgrav... I did not check the parts that he said he had no problems with. He forgot the factor of pi.

Pat
 

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