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Stuck with finding function from graph of its derivative.

  1. Sep 24, 2009 #1
    So the question asks me to use the following information to graph the function f over the closed interval [-2, 5]
    i) The graph of f is made of closed line segments joined end to end.
    ii) The graph starts at the point (-2, 3)
    ii) The derivative of f is the step function in the figure shown here.
    That's all give as well as a graph, but I don't know how to put a graph on so I'll just state it's points.
    x: [-2 to 0) y' = -2
    x: (0 to 1) y' = 0
    x: (1 to 3) y' = 1
    x: (3 to 5] y' = -1


    I am totally clueless of what to do, I missed that class and wasn't able to catch up to what I missed. I tried reading through the text to see if it says anything about this but found nothing. I know y' is basically the slope of f(x), and I know how to do integration (but I am not allowed to use it, as we haven't gotten there yet). Anyways, my point is I tried integrating the y' but yea, it just makes no sense to me. I hate graphs.
    I would love any idea, I just wish to understand how to do this and then I'll be fine figuring out the rest.
     
  2. jcsd
  3. Sep 24, 2009 #2
    The derivative of a function at a point is just the slope of the function at that point. Does that help?
     
  4. Sep 24, 2009 #3
    Yea i figured that out, so that mean the line of the derivative is just the slope of the original graph?
     
  5. Sep 24, 2009 #4
    I don't know what that question means. What is the line of the derivative?

    The value of the derivative at a point is the slope of the original function at that point.

    For example.

    If y' = 2 then the slope of y at x is 2.
     
  6. Sep 24, 2009 #5
    Ah, I got it. Thanks a lot.
     
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