Sublimation of Dry Ice in a Closed System

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In a closed system, frozen water can convert to liquid if the temperature exceeds 0°C, as water is denser than ice and requires no additional space. Conversely, water cannot freeze into ice in a closed container below 0°C due to lack of space for expansion. Dry ice will not sublimate in a closed container if the temperature remains below -78.5°C, but the risk of pressure buildup depends on the container's wall strength and thickness. The boiling points of substances vary with pressure, meaning that in a high-pressure environment, sublimation may not occur even if external temperatures rise. Ultimately, the ability of dry ice to sublimate in a closed system is contingent on both temperature and the structural integrity of the container.
Inquirer18
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Hello,

Please forgive my ignorance, although bright, I was a lousy student, & never took physics in school. I find it frustrating when relatives & friends are uncertain as to how to respond to questions like those below, so your educated reply would therefore be all the more appreciated. Thank you.

I would assume that frozen H20 completely filling the space of a closed system would convert to water if the container (one whose walls consisted of an energy conductor such as aluminum) would be placed in an environment above 0 Celsius, since extra room is not required for the newly formed water, as water is denser than ice. However, the converse, would probably not be true, as when placing the same container, this time filled completely with water in a room where the temperature is below 0 Celsius, since the water would have no room to expand when attempting to convert to a solid. Similarly, I would assume that dry ice completely filling a container, as the one described above, would not sublimate, when the container is placed in a room above -78.5 degrees Celsius. I understand that in the dry ice example, the container's walls would have to be sufficiently thick to offset the increasing pressure buildup resulting from sublimation. But if the inside of the container were, say, one square foot, and the walls of the container would be a foot thick, and instead of aluminum have the walls of the container made of titanium, would the dry ice sublimate without risk of explosion or would the pressure buildup not allow the dry ice to sublimate?
 
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Inquirer18 said:
But if the inside of the container were, say, one square foot, and the walls of the container would be a foot thick, and instead of aluminum have the walls of the container made of titanium, would the dry ice sublimate without risk of explosion or would the pressure buildup not allow the dry ice to sublimate?

This would still rather depend on the strength of the walls and all that. A little difficult to say. Also, the boiling points of substances are measured at a known pressure. A liquid in a low pressure environment has a lower boiling point than when the liquid is at atmospheric pressure. Likewise, a liquid in a high pressure environment has a higher boiling point than when the liquid is at atmospheric pressure. The values you have are for atmospheric pressure, I think.
 
All solids & liquids described above begin at atmospheric pressure. The question is does the temperature on the exterior of the container walls (namely the temperature in the room the container is situated in.) which is attempting to elevate the temperature of the dry ice within the container succeed in elevating the temperature within or does it not succeed? And if it does succeed is the dry ice able to sublimate or not? I wonder if the dry ice's temperature can only be elevated if it would be able to sublimate? In my example (if you'd prefer, we could talk about the walls being 100 feet thick. I don't really care how thick as long as they are sufficiently thick to NOT allow the pressure buildup to ever be able to cause the container to explode).
 
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