Summation Notation for Weak form of Differential Equation

AI Thread Summary
The discussion revolves around the transformation of summation notation into integral form in the context of weak forms of differential equations. The user is seeking clarification on how the summation over intervals translates into an integral and the implications of this transformation. It is noted that the integration property, which allows combining integrals over adjacent intervals, plays a crucial role in this process. The intermediate terms in the equation represent the boundary contributions at each interval, which are explicitly detailed. Overall, the conversation highlights the connection between discrete summation and continuous integration in mathematical formulations.
bugatti79
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Folks,

I am struggling to see what is happening here particularly when ## \displaystyle \sum_{i=1}^{n-1}## transforms into ##\displaystyle \int_{x_1^e}^{x_{n}^e}##

##\displaystyle 0=\sum_{i=1}^{n-1} \left [ \int_{x_i^e}^{x_{i+1}^e} (a \frac{dw}{dx} \frac{du}{dx}+cwu-wf )dx- \left [ w(x) a \frac{du}{dx} \right ]_{x_i^e}^{x_{i+1}^e} \right ]##

##\displaystyle =\int_{x_1^e}^{x_{n}^e} (a \frac{dw}{dx} \frac{du}{dx}+cwu-wf )dx -w(x_1^e) (-a \frac{du}{dx})_{x_1^e}-w(x_2^e) (a \frac{du}{dx})_{x_2^e}-w(x_2^e) (-a \frac{du}{dx})_{x_2^e}-w(x_3^e) (a \frac{du}{dx})_{x_3^e} ...-w(x_{n-1}^e) (-a \frac{du}{dx})_{x_{n-1}^e}-w(x_{n}^e) (a \frac{du}{dx})_{x_{n}^e}##

Could anyone shed some light on what is happening..?

Apparently it is carried out in intervals of ##(x_1^e, x_2^e), (x_2^e, x_3^e),(x_{n-1}^e, x_n^e)##

Thanks
 
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I am no expert on this, but I think he's using a the property of integration
\int^{b}_{a} f + \int^{c}_{b} f = \int^{c}_{a} f
the intermediate terms are just writing out the [w(x)a\frac{du}{dx}]^{x^{e}_{i+1}}_{x^{e}_{i}} explicitly
 
dragonlorder said:
I am no expert on this, but I think he's using a the property of integration
\int^{b}_{a} f + \int^{c}_{b} f = \int^{c}_{a} f
the intermediate terms are just writing out the [w(x)a\frac{du}{dx}]^{x^{e}_{i+1}}_{x^{e}_{i}} explicitly

Thanks. That helps my interpretation. I knew the intermediate terms.
Regards
 
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