Summation - Riemann Intergral -

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SUMMARY

The discussion focuses on calculating the upper and lower Riemann sums for the function f(x) = exp(-x) over the interval [0,1]. The upper sum is correctly identified as the limit of the sum from i=1 to n of exp(-i/n)/n as n approaches infinity. The lower sum is proposed as the sum from i=1 to n of exp((1-i)/n)/n. Both sums are essential for approximating the definite integral of the function using Riemann sums.

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[SOLVED] Summation - Riemann Intergral - URGENT

Homework Statement



Im working on the upper and lower riemann sums of f(x) = exp(-x)

where Pn donates the partition of [0,1] into n subintervals of equal length (so that Pn = {0,1/n,2/n,...,1})


Homework Equations





The Attempt at a Solution



So far i have the upper sum to be the sum from i=1 to n of exp(-i/n)/n - is this right? - if so where do i go from here? I think I am meant to take the limit when n-> infin which should give the final upper sum. I hope this right...
 
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...and the lower sum to be the sum from i=1 to n of exp((1-i)/n)/n ?
 

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