Sumobot Competition: Torque vs RPM?

AI Thread Summary
In a sumobot competition with a 1kg weight limit and 150mm x 150mm dimensions, the debate centers on whether to prioritize torque or RPM for motor selection. Higher torque is recommended for better load handling, similar to how a truck operates efficiently despite low RPM. However, gearing down a higher RPM motor can significantly increase its effective torque, making it a viable option if power is maximized. It's crucial to consider the trade-off between speed and torque after gearing, as motor performance varies with RPM. Ultimately, the choice should focus on achieving the best balance of power and torque for optimal performance in the competition.
sarathyplkr5
Messages
2
Reaction score
0
hi .. ...
i am entering a sumobot competition..weight limitation 1kg..dimensions 150mm*150mm...what is more important
torque or rpm...say i have 10 rpm motors with 38kg torque ...and ..60 rpm motors with 20 kg torque...which should i go for...due to the size limitation ..i can go only for 2 motors...any comment is appreciated... Wink
 
Physics news on Phys.org
Every single things are not perfect. They will come with pros and cons. With this kind of competition, I would go for TORQUE.

Put it this way, just imagine a big truck can carry a load that heavier than its weight. Even it move at low rpm but still can pull its load with high torque.

In your case, you are about to build a sumo robot, I suggest you go for a motor that has a higher torque than rpm itself.

Just my humble opinions.
 
thanks a lot...
 
sarathyplkr5 said:
hi .. ...
i am entering a sumobot competition..weight limitation 1kg..dimensions 150mm*150mm...what is more important
torque or rpm...say i have 10 rpm motors with 38kg torque ...and ..60 rpm motors with 20 kg torque...which should i go for...due to the size limitation ..i can go only for 2 motors...any comment is appreciated... Wink

If you gear down the 60 rpm motor to 10rpm, it will give you 6 times the torque it had at 60 rpm. What matters is power = torque x angular velocity. In your example the 60 rpm motor has much more power, so it can potentially create more torque at the same angular velocity.
 
Assuming you can gear the motors, then you're looking for power that is geared down so that the geared down and multiplied torque is at a maximum. See if you can get the specific motor performance curves for the two motors you're considering.

Note that electrical motors usually produce peak power at 1/2 the maximum no load rpm, but will generate more torque at lower rpms than higher rpms. Link to article that explains this:

dc_motors.html

You'll need to decide on a trade off of speed versus the torque after gearing reduction of your bot when choosing the motor and the gearing.
 
Hello everyone, Consider the problem in which a car is told to travel at 30 km/h for L kilometers and then at 60 km/h for another L kilometers. Next, you are asked to determine the average speed. My question is: although we know that the average speed in this case is the harmonic mean of the two speeds, is it also possible to state that the average speed over this 2L-kilometer stretch can be obtained as a weighted average of the two speeds? Best regards, DaTario
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top