Super-hard differential equation in classical mechanics problem

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Homework Help Overview

The problem involves a particle of mass m moving in a repulsive potential field described by U(x) = α/x², where α is a positive constant. The objective is to determine the trajectory x(t) given specific initial conditions.

Discussion Character

  • Exploratory, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to derive the second-order differential equation from the potential energy function but expresses frustration with the complexity of the equation. Some participants suggest methods to manipulate the equation, such as multiplying by x' to simplify it into exact differentials.

Discussion Status

Participants are exploring different approaches to tackle the differential equation. Some guidance has been offered regarding techniques that may simplify the problem, but there is no explicit consensus on the best method to proceed.

Contextual Notes

The original poster expresses difficulty with the problem, indicating a level of frustration. There are references to external resources and techniques that may or may not be applicable, highlighting the uncertainty in the approach to the differential equation.

snaek
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Homework Statement


A particle of mass m moves in the following (repulsive) field
U(x) = α/x², α > 0,
with α a constant parameter. Determine the (unique) trajectory of the particle, x(t), corresponding to the initial conditions of the form

x(t0) = x0 > 0,

x'(t0) = [itex]\sqrt{\frac{2}{m}(E-\frac{α}{(x0)^2})}[/itex]

Homework Equations



^

The Attempt at a Solution



mx''(t) = -d/dx U(x)
= - (2α/x³)
= 2α/x³

=> x''(t) = 2α/mx³

Would anyone please be able to point me on the right track to solving this stupid DE? It's really starting to mess with my mind now!
 
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You can solve your "stupid" DE by multiplying both sides of the equation by x'. This will give you exact differentials on both sides.
 
snaek said:
=> x''(t) = 2α/mx³

Would anyone please be able to point me on the right track to solving this stupid DE? It's really starting to mess with my mind now!
The DE always speaks well of you.

Chestermiller said:
You can solve your "stupid" DE by multiplying both sides of the equation by x'. This will give you exact differentials on both sides.
This is a good trick to remember.
 

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