Superposition Method for Finding Vout: Steps and Equations Explained

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SUMMARY

The discussion focuses on applying the Superposition Method to find output voltages Vout1 and Vout2 in a circuit analysis problem. The user successfully calculated Vout1 as 0.85V by shorting the voltage source and performing DC analysis. However, they encountered difficulties in calculating Vout2 after opening the current source, leading to confusion about the circuit configuration and resistor arrangements. The solution involves redrawing the circuit without the current source and using Kirchhoff's Voltage Law (KVL) and Kirchhoff's Current Law (KCL) for further analysis.

PREREQUISITES
  • Understanding of Superposition Theorem in circuit analysis
  • Familiarity with Kirchhoff's Voltage Law (KVL)
  • Knowledge of Kirchhoff's Current Law (KCL)
  • Basic DC circuit analysis techniques
NEXT STEPS
  • Study the application of the Superposition Theorem in complex circuits
  • Learn to redraw circuits for analysis after removing sources
  • Practice using KVL and KCL in various circuit configurations
  • Explore resistor combinations and their effects on circuit behavior
USEFUL FOR

Electrical engineering students, circuit designers, and anyone involved in circuit analysis looking to deepen their understanding of the Superposition Method and related laws.

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Homework Statement



See pdf attachment named Superposition .Find Vout

Homework Equations



Steps of Superposition

The Attempt at a Solution



I fount Vout1 by replacing the voltage source with a short circuit and doing basic d.c. analysis. My answer = 0.85V

However I'm stuck on how to find Vout2. I know you have to replace the current source with an open circuit. This however confuses me as there is now an open circuit in the middle of my circuit and I'm unsure what resistors, if any are in parallel and how to find the voltage across the load which is Vout2

Any help is greatly appreciated.

Thanks
 

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I am not sure which V you are talking about. That network is really confusing to look at.

Could you maybe post your calculations for how you found Vout1 so I can tell where you are coming from?

However I'm stuck on how to find Vout2. I know you have to replace the current source with an open circuit. This however confuses me as there is now an open circuit in the middle of my circuit and I'm unsure what resistors, if any are in parallel and how to find the voltage across the load which is Vout2

So, for superposition, you know that you short Vsources and open Isources.

Now, you say that you are confused because there would be an open circuit in the middle of the circuit?

Well, that's not completely true. You would be "opening" the current source, which means you just re-draw the circuit without the current source and perform your analysis again.

Since all you have left is a Vsource, I would recommend using KVL to find all of the currents. That's a hint that you should use KCL to find all of the voltages.

The more I look at the circuit, I wonder why you are using superposition anyway?
 

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