Surface area of parametric equation

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Pete_01
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Homework Statement


For the surface with parametric equations r(st)=<st, s+t, s-t>, find the equation of the tangent plane at (2,3,1).
Find the surface area under the restriction s^2 + t^2 <=(lessthanorequalto) 1


Homework Equations





The Attempt at a Solution


I already figured out the equation of the tangent plane: -2x+3y-z=4, but I am not sure how to find the surface area? I want to use the SA equation |rs x rt| integrated from ds 0 to 1 and dt 0 to 2pi but i am not having much luck. Any ideas?
 
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Pete_01 said:

Homework Statement


For the surface with parametric equations r(st)=<st, s+t, s-t>, find the equation of the tangent plane at (2,3,1).
Find the surface area under the restriction s^2 + t^2 <=(lessthanorequalto) 1


Homework Equations





The Attempt at a Solution


I already figured out the equation of the tangent plane: -2x+3y-z=4, but I am not sure how to find the surface area? I want to use the SA equation |rs x rt| integrated from ds 0 to 1 and dt 0 to 2pi but i am not having much luck. Any ideas?

If you are integrating with dA=ds dt, from ds 0 to 1, then dt would be 0 to [tex]\sqrt{1-s^2}[/tex]. Try converting the double integral to polar coordinates with dA=r dr d_theta.