Evaluate Surface Integral f.n ds for Sphere x^2+y^2+z^2=a^2

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To evaluate the surface integral of the vector field f = xi + yj - 2zk over the upper hemisphere of the sphere defined by x^2 + y^2 + z^2 = a^2, one can utilize spherical coordinates due to the symmetry of the problem. The normal vector n to the surface must be determined first, as it is essential for calculating the flux. The vector field is anti-symmetric about the origin, which suggests that the integral may yield zero over the symmetric region. Alternatively, applying the Divergence Theorem allows for the integration of the divergence of f over the volume of the sphere, simplifying the computation. This approach highlights the relationship between the vector field's properties and the geometric characteristics of the sphere.
anand
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Problem : Evaluate [double integral]f.n ds where f=xi+yj-2zk and S is the surface of the sphere x^2+y^2+z^2=a^2 above x-y plane.

My effort:: I know that the sphere's orthogonal projection has to be taken on the x-y plane,but I'm having trouble with the integration.Please help!
 
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Calculating flux integrals can be a bit tedious. Although some are very easy when you invoke the right theorem. Like this one.
 
anand said:
Problem : Evaluate [double integral]f.n ds where f=xi+yj-2zk and S is the surface of the sphere x^2+y^2+z^2=a^2 above x-y plane.

My effort:: I know that the sphere's orthogonal projection has to be taken on the x-y plane,but I'm having trouble with the integration.Please help!

you want to find f.n where n is obviously the normal to the surface .. find that first... the easiest way to do this is probably change to spherical coordinates...given the symmetry of the problem
 
Didn't we just have this question? Or was it also posted on a different board?

The vector function, f(x,y,z)= xi+ yj- 2zk, is obviously "anti-symmetric" about the origin: f(-x,-y,-z)= -(f(x,y,z)), while the region of integration, a sphere centered at the origin, is symmetric. What does that tell you?

Or you can use the "Divergence theorem" and integrate \nabla \cdot f over the interior of the sphere, as Galileo suggested. Here \nabla \cdot f is particularly simple.
 

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