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ilp89
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Does Sylvester's Criterion hold for infinite-dimensional matrices? Thanks!
ilp89 said:Does Sylvester's Criterion hold for infinite-dimensional matrices? Thanks!
ilp89 said:Well, Sylvester's criterion only requires us to find determinants of the principal minors, which are all finite square matrices. There are just an infinite number of them.
ilp89 said:I guess if all principal minors are positive, then the infinite matrix is the limit of positive definite matrices and is thus positive semi-definite.
Sylvester's Criterion for Infinite-dimensional Matrices is a mathematical theorem that states that a matrix is invertible if and only if its determinant is non-zero. This criterion applies to infinite-dimensional matrices, which are matrices with an infinite number of rows and columns.
In the finite-dimensional case, a matrix is invertible if and only if its determinant is non-zero. However, in the infinite-dimensional case, this criterion still holds true, but it is not sufficient. Additional conditions must be met for an infinite-dimensional matrix to be invertible, as the concept of determinant becomes more complex in this scenario.
Sylvester's Criterion for Infinite-dimensional Matrices is used in various fields such as functional analysis, differential equations, and quantum mechanics. It is particularly useful in studying infinite-dimensional linear transformations and operators.
No, Sylvester's Criterion for Infinite-dimensional Matrices only applies to linear operators. Non-linear operators do not have a determinant, so this criterion cannot be extended to them.
Sylvester's Criterion for Infinite-dimensional Matrices provides a necessary and sufficient condition for a matrix to be invertible. This means that if the determinant of an infinite-dimensional matrix is non-zero, then the matrix is invertible, and if the determinant is zero, the matrix is not invertible. In other words, the criterion is a way to determine the invertibility of an infinite-dimensional matrix.