Symmetry in Differential Equations: Benefits & Consequences

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Hello everybody!

I have a general question concerning DEs :0

Can one use the symmetry of the equation to somehow get the solution faster?
What does such symmetry tell us?
e.g.:
\dot x=y
\dot y=x

is the symmetrical system to the second order DE

\ddot x-x=0

Now we can easily see the solutions (whether e^t or e^(-t)) actually have the same properties as functions. They are even one and the same function, rotated over the y-axis!

So, is the symmetry really providing help or this is just a coincidence?
 
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Marin said:
… So, is the symmetry really providing help or this is just a coincidence?

Hello Marin! :smile:

Well … if x' = y2

y' = x2

then x'' = 2y y' = 2x2 √x'

so that's a symmetry which is no help at all! :cry:

(I suspect there's a condition that makes it helpful … perhaps something like the Jacobian being unitary … but I'll let someone else answer that! :wink:)
 
tiny-tim said:
Hello Marin! :smile:

Well … if x' = y2

y' = x2

then x'' = 2y y' = 2x2 √x'

so that's a symmetry which is no help at all! :cry:

(I suspect there's a condition that makes it helpful … perhaps something like the Jacobian being unitary … but I'll let someone else answer that! :wink:)


Sorry,tiny-tim, couldn't quite get it :(

What's the purpose of "then x'' = 2yy' = 2x2 √x'"

When I look at the system itself, what I see is that what's true for y should be true for x which to my understanding implies that the two functions are somehow similar to one another..

And the big question is, if so, then HOW?

**maybe my question above should be: Does the symmetry of a system of simultaneous DEs provide us somehow to find the solution faster?
 
Marin said:
When I look at the system itself, what I see is that what's true for y should be true for x which to my understanding implies that the two functions are somehow similar to one another.

oh I see!

Then, yes, both x and y are solutions to the same equation, so they will be different combinations of the same basic solutions. :smile:

(But I don't see how that would generally help.)
 
well, if we could find one solution, e.g.:

dy/dx=x^2 => y=1/3 x^3 +c

it is true then that x=1/3y^3 +c

but if x and y are basically the same functions, do we have?:

1/3 x^3=1/3y^3 +k /.3
x^3=y^3 +c

which I think is the solution to the DE, from which the system has been derived, cuz:

the system was:

dx/dt=y^2
dy/dt=x^2

now dividing the second equation by the first one (to eliminate dt):

dy/dx=x^2/y^2 - which is same with the result above.

Was it just a coincidence or is there some symmetry in it?

EDIT: Sorry, I didn't pay attention I used different variables ( first x and then t)
 
Hi Marin! :smile:
Marin said:
dx/dt=y^2
dy/dt=x^2

now dividing the second equation by the first one (to eliminate dt):

dy/dx=x^2/y^2 - which is same with the result above.

Was it just a coincidence or is there some symmetry in it?

Yes, I didn't think of that. :redface:

So long as the right-hand side is a function of only one variable,

we can always divide one equation by the other (as you did):

if dx/dt = f'(y), dy/dt = f'(x), say

then f'(y)dy = f'(x)dx,

so f(y) = f(x) + constant. :smile:

You're right … the symmetry does help! :smile:
 
And what about the other cases?

consider the system:

\dot x=x+y^2-2t
\dot y=x^2+y-2t

to be honest, I don't have an idea how to solve it analytically :(

But it's symmetrical... You were talking about the Jacobian hmmm could it be an ansatz here ?
 
Marin said:
And what about the other cases?

consider the system:

\dot x=x+y^2-2t
\dot y=x^2+y-2t

to be honest, I don't have an idea how to solve it analytically :(

But it's symmetrical... You were talking about the Jacobian hmmm could it be an ansatz here ?

Sorry, I've no idea.

Just guessing about the Jacobian … someone else wil have to answer that. :redface:
 
Does anybody know something about it?
 
  • #10
Marin said:
consider the system:

\dot x=x+y^2-2t
\dot y=x^2+y-2t

Hm... look like a challenging problem. Never seen before. Is there any application for this system?

Look like you all been thinking of reflection symmetry x \leftrightarrow y before. May be we should be looking at other transformation such that system remain invariant. Is Lie symmetry is of any used here ? I don't know.

I will monitor this thread. Hopefully somebody could answered it.
 
  • #11
Well, these systems have no physical meaning (at least are not meant to have here). I am interested in the problem from a pure mathematical point of view.

Look like you all been thinking of reflection symmetry x \leftrightarrow y before
- absolutely true - I consider it the most obvious one - if we could find something interesting about it, maybe we could then ask for partial symmetries or negative symmetry, etc.

I know many DEs are not analytically solvable, and many others take a lot of time to find a solution. That's why I'm asking about these symmetrical systems. I think there must be something 'invisible' to us, but hidden in the system.


I would be glad to see every comment or idea - more or less probable :)

best regards, Marin
 
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