System of differential equations - a big problem solving it

[ILens]

Hi!

I have a serious problem solving the following system of differential equations:

<br /> m_1\ddot{x_1}=-k_1x_1-k(x_1-x_2)<br />

<br /> m_2\ddot{x_2}=-k_2x_2-k(x_2-x_1)<br />
​

Does anybody have an idea how to solve it?

Thanks.

 

[dextercioby]

It can be easily decoupled obtaing a 4-th order ODE in one of the coordinates.Which can be solved.

 

[ILens]

Thank you, but you told me something that I already know. I have problems deriving these equations. Would you mind being more explicit in your answer.

 

[dextercioby]

From the first equation express x2 as a function of x1 and its second derivatives and puti it in the second equation.You'll get the 4-th order LODE.Make simplifications assuming the masses are the same.in that case,formulas will get smaller in size.

 

[ILens]

Thanks for your answer.

You have just confirmed that the solution I have derived is correct

 

[Dr Transport]

The equations can be solved by two methods, set both x_{1} and x_{2} equal to complex exponentials with different constant coefficients then plug away, you'll get an algebraic set of equations to solve, the other way is to take sums and differences of them and use another coordinate system like y_{i} = x_{1} \pm x_{2} and work thru using the method in the first part of this reply.

There is no need to get into a 4th order ODE.

 

[Tide]

Laplace Transforms, anyone? :-)

 

[Dr Transport]

Let x_{i} = a_{i}e^{i\omega t}, substitute and get the following equations

-a_{1}m_{1}\omega^{2} = -a_{1}k_{1} - k(a_{1} - a_{2})

-a_{2}m_{2}\omega^{2} = -a_{2}k_{2} - k(a_{2} - a_{1})

Solve this set of equations for \omega the use the boundary and initial conditions to obtain the a_{1} and a_{2}. This is a complicated set of equations because of the 3 distinct spring constants. at first glance it was exactly solvable almost trivial, but 3 constants makes it an order of magnitude more difficult.