MATLAB System of differential equations

AI Thread Summary
The discussion revolves around solving the equations of motion for a planet using MATLAB. The initial equations for forces in the x and y directions are presented, and the user attempts to implement these equations in a MATLAB function. However, the results are incorrect due to several issues, including a misunderstanding of how to update position and velocity in the state vector. Key points include the realization that the user incorrectly set the output for position updates and neglected to include a crucial minus sign in the force equations. It is suggested to use the ode113 solver instead of ode45 for better accuracy in orbital dynamics, as ode113 is a variable order solver that can handle precision better. The discussion also highlights the importance of correct initial conditions and understanding MATLAB's numerical integration methods.
dRic2
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Hi, I was trying to solve the simplest problem of planetary motion (for one planet).

The equations should be:

##F_x = m \frac {d^2x} {dt^2} = G \frac {Mmx} {r^3}##
##F_y = m \frac {d^2y} {dt^2} = G \frac {Mmy} {r^3}##

where ## r = \sqrt{x^2 + y^2}##

So I re-wrote the system like this:

##\frac {dx} {dt} = v_x##
##\frac {dy} {dt} = v_y##
##\frac {dv_x} {dt} = G \frac {Mmx} {r^3}##
##\frac {dv_y} {dt} = G \frac {Mmy} {r^3}##

I'm not sure how to implement this in matlab...

I tried this

Code:
function out = sis(t, s)

% s(1) is x
% s(2) is y
% s(3) is v_x
% s(4) is v_yglobal G Ms Mt
out = zeros(4,1);out(1) = s(3);

out(2) = s(4);r = sqrt(s(1)^2 + s(2)^2);out(3) = G * Ms * Mt * s(1) / (r^3);

out(4) = G * Ms * Mt * s(2) / (r^3);end

but It gives wrong results.

Thanks
Ric
 
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Why do you set out(1) = s(3) and out(2) = s(4) shouldn't they be something like out(1) = s(1) + t*s(3) and out(2) = s(2) + t*s(4) ?

and is the v_z really v_y?
 
jedishrfu said:
and is the v_z really v_y?
yes, my bad.

jedishrfu said:
Why do you set out(1) = s(3) and out(2) = s(4) shouldn't they be something like out(1) = s(1) + t*s(3) and out(2) = s(2) + t*s(4) ?

I want to use ode45 instead of manually implement the algorithm and I though that is the way to do it.
 
You misunderstood what I was asking. My understanding is that the s array is the state of the system and since s1 and s2 represent the position then you must update the position each time with a delta x and a delta y value.

The delta x is in fact ##vx * \Delta t## which in your case is t giving the ##out1=s1+vx*t## expression.

Do you see what I mean?
 
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dRic2 said:
but It gives wrong results.
You'll have to elaborate.
 
Thanks @jedishrfu, very nice link!

First of all, I forgot the minus sign in front of $\frac GMmx/r^3$. And then, as concerned as I was with mathematics, I totally forgot about the physics of the problem! My initial conditions were wrong and physically inconsistent so the numerical integration kept failing.
 
Try ode113 instead of ode45, as it is a variable order solver that includes the results of several past time steps. It is better than ode45 for problems where high precision is required, such as orbital dynamics problems.

Example here:
https://www.mathworks.com/help/matlab/ref/ode113.html#bu6t62o-1_1

ode45 actually outputs more points than it computes - it uses interpolation to get a few extra points per time step, which results in nicer looking plots. That can be adjusted with the 'Refine' option.
 
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Thanks @Krell. I was just experimenting with Matlab to get used to it, but it is very useful to know!
 

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