T: What is the Minimum Distance for No Slipping in Static Equilibrium?

  • Thread starter Thread starter nameVoid
  • Start date Start date
  • Tags Tags
    Static
Click For Summary
SUMMARY

The discussion focuses on calculating the minimum distance \( x \) from a wall for a rod of length 4m and weight \( F_g \) to avoid slipping in static equilibrium. The rod is supported by a cable at a 37-degree angle, with a static friction coefficient of 0.5 between the wall and the rod. Key equations include the sum of forces in the x-direction \( R_x - T \cos(37) = 0 \), the sum of forces in the y-direction \( R_y + T \sin(37) - F_s - 2F_g = 0 \), and the torque equation \( 4T \sin(37) - 2F_g - xF_g = 0 \). The wall force \( R \) and tension \( T \) are critical components in determining the equilibrium conditions.

PREREQUISITES
  • Understanding of static equilibrium principles
  • Knowledge of torque and force analysis
  • Familiarity with trigonometric functions in physics
  • Basic concepts of friction, specifically static friction
NEXT STEPS
  • Study the application of static equilibrium in mechanical systems
  • Learn about torque calculations in different contexts
  • Explore the effects of varying angles on tension and friction
  • Investigate the role of coefficients of friction in stability analysis
USEFUL FOR

Students and professionals in physics, engineering, and mechanics who are analyzing static systems and stability, particularly those dealing with forces and torques in equilibrium scenarios.

nameVoid
Messages
238
Reaction score
0
a rod of length 4m and weight Fg is supported at one end by a cable attached to a wall that makes an angle of 37 degrees with the rod. an object of equal weight is a distance of xm from the wall. the coefficient of static friction between the wall and the rod is .5 determine the minimum distance x from the wall for no slipping.

taking R as the wall force and T ans the tension in the cable

sum Fx = Rx-Tcos37=0
sum Fy = Ry+Tsin37-Fs-2Fg=0
sum torque = 4Tsin37-2Fg-xFg=0

not sure how to deal with the wall force
 
Physics news on Phys.org
nameVoid said:
a rod of length 4m and weight Fg is supported at one end by a cable attached to a wall that makes an angle of 37 degrees with the rod. an object of equal weight is a distance of xm from the wall. the coefficient of static friction between the wall and the rod is .5 determine the minimum distance x from the wall for no slipping.

taking R as the wall force and T ans the tension in the cable

sum Fx = Rx-Tcos37=0
sum Fy = Ry+Tsin37-Fs-2Fg=0
sum torque = 4Tsin37-2Fg-xFg=0

not sure how to deal with the wall force
I'm not sure where the weight is. Is it hanging from the rod?

Anyhow, the force of static friction depends on the normal force on the wall ie. into the wall. What is the force toward the wall exerted by the rod?

AM
 

Similar threads

Finding the Minimum Distance for Static Equilibrium with a Hanging Weight
  • · Replies 8 ·
Replies
8
Views
5K
Equilibrium of a Rod Problem: Find Minimum Distance x
  • · Replies 31 ·
2
Replies
31
Views
10K
Static Equilibrium - Ladder problem with a twist.
  • · Replies 7 ·
Replies
7
Views
4K
Rigid Objects In Static Equilibrium: Mass on a Bar
  • · Replies 5 ·
Replies
5
Views
6K
Static Equilibrium of a 10m Rod with a Hanging Weight at 1.46m Distance
  • · Replies 1 ·
Replies
1
Views
1K
Minimum angle the ladder can make with the floor without slipping
  • · Replies 7 ·
Replies
7
Views
15K
Coefficient of static friction of uniform rod
  • · Replies 2 ·
Replies
2
Views
2K
What is the minimum force at this angle that will move the box?
  • · Replies 12 ·
Replies
12
Views
5K
Why is there a vertical force on the pin in this static equilibrium setup?
  • · Replies 8 ·
Replies
8
Views
2K
How Is Torque Equilibrium Applied to a Sphere Tethered to a Wall?
  • · Replies 5 ·
Replies
5
Views
7K