T: What is the Minimum Distance for No Slipping in Static Equilibrium?

[nameVoid]

a rod of length 4m and weight Fg is supported at one end by a cable attached to a wall that makes an angle of 37 degrees with the rod. an object of equal weight is a distance of xm from the wall. the coefficient of static friction between the wall and the rod is .5 determine the minimum distance x from the wall for no slipping.

taking R as the wall force and T ans the tension in the cable

sum Fx = Rx-Tcos37=0
sum Fy = Ry+Tsin37-Fs-2Fg=0
sum torque = 4Tsin37-2Fg-xFg=0

not sure how to deal with the wall force

 

[Andrew Mason]

a rod of length 4m and weight Fg is supported at one end by a cable attached to a wall that makes an angle of 37 degrees with the rod. an object of equal weight is a distance of xm from the wall. the coefficient of static friction between the wall and the rod is .5 determine the minimum distance x from the wall for no slipping.

taking R as the wall force and T ans the tension in the cable

sum Fx = Rx-Tcos37=0
sum Fy = Ry+Tsin37-Fs-2Fg=0
sum torque = 4Tsin37-2Fg-xFg=0

not sure how to deal with the wall force

I'm not sure where the weight is. Is it hanging from the rod?

Anyhow, the force of static friction depends on the normal force on the wall ie. into the wall. What is the force toward the wall exerted by the rod?

AM