(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

One end of a uniform 4.00m long rod of weight F_{g}is supported by a cable. The cable is attached to the bar at an angle of 37.0^{o}. The other end of the bar rests against the wall where its held by friction. The coefficient of static friction between the wall and the rod is [tex]\mu[/tex]_{s}=0.500. Determine the minimum distance x from point A at which an additional object with the same weight F_{g}can be hung without causing the rod to slip off the wall.

2. Relevant equations

[tex]\Sigma[/tex]F_{x}= F_{h}-Tcos37=0

[tex]\Sigma[/tex]F_{y}= 0.500-F_{go}-F_{gb}+Tsin37=0

[tex]\Sigma[/tex][tex]\tau[/tex]_{z}= x(F_{go})-2(F_{gb})+4Tsin14=0

Since the two weights are equal can I add them together in the equations and call it 2F? I was thinking I couldn't do this because the additional object's weight will be in a different area than the center of gravity of the beam. Also my subscripts are go is the object and gb is the beam. Fh is the horizontal force of the wall on the beam.

3. The attempt at a solution

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# Homework Help: Rigid Objects In Static Equilibrium: Mass on a Bar

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