Equilibrium of a Rod Problem: Find Minimum Distance x

  • Thread starter Thread starter burnst14
  • Start date Start date
  • Tags Tags
    Equilibrium Rod
Click For Summary

Homework Help Overview

The discussion revolves around a problem involving the equilibrium of a uniform beam supported by a cable and friction. The beam's length, the angle of the cable, the coefficient of static friction, and the weight of the beam are specified. Participants are tasked with determining the minimum distance from a support point at which an additional weight can be hung without causing the beam to slip.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants explore the relationships between forces acting on the beam, including normal force, friction, and torques. There are attempts to set up equations for force components and moments, with some questioning the assumptions made about the forces involved.

Discussion Status

Several participants have provided equations and attempted to manipulate them to express variables in terms of others. There is ongoing exploration of how to relate the normal force to the weight of the beam and the friction force. Some participants express uncertainty about the correctness of their equations and seek clarification on algebraic manipulations.

Contextual Notes

Participants note the challenge of solving for multiple variables with limited known quantities, and there is discussion about the implications of assuming maximum friction. The problem is framed within the constraints of an online homework platform that allows multiple attempts for solutions.

  • #31
burnst14 said:
Alright I got the right answer using your value. I'm not sure how you got it though. That seems to be new to me.

[cos30-(sin30/-μ)]FB = 3w/-μ

FB = [(-3w/-μ)/(cos30-(sin30/-μ)]

This is almost exactly the equation I got. Just multiply the numerator and denominator by ##\mu##.

FB = (-3w/-μ)[(1/cos30)-(-μ/sin30)

This is wrong. You cannot go from ## \frac {a} {b + c} ## to ## a(\frac 1 b + \frac 1 c)##, these are not equal.

As for the tool, click the Quote button on my message, you will see some code there. That code is LaTeX. When you are in (advanced) reply screen, there is a ##\sum## button, which you can use to find codes for whatever math symbol you need. Or you can just search for a LaTex reference online.
 
  • Like
Likes   Reactions: 1 person
Physics news on Phys.org
  • #32
Alright thank you. Oh okay. I'll use that next time. Thanks for all the help. This forum is great.
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
3K
Replies
2
Views
2K
  • · Replies 6 ·
Replies
6
Views
4K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 7 ·
Replies
7
Views
4K
  • · Replies 42 ·
2
Replies
42
Views
4K
Replies
1
Views
2K
  • · Replies 21 ·
Replies
21
Views
4K
Replies
19
Views
3K