Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Take a look at this simple circuit please.

  1. Dec 6, 2011 #1
    attachment.php?attachmentid=41645&stc=1&d=1323231361.jpg

    Here if we convert the 12V Voltage source in series with 3K resistor to current source
    we get 4mA current in parallel with 3k resistor and this 4mA will be entering node 1 right ?
    so 4mA is entering node 1 and 4mA is leaving to ground at node 2

    so the current Io (from node 1 to ground ) should be zero right ?
    How is he getting 1mA ?

    P.S.
    If his answer is wrong I'm gonna sue this author for wasting my time giving wrong answers :/
     

    Attached Files:

  2. jcsd
  3. Dec 7, 2011 #2

    vk6kro

    User Avatar
    Science Advisor

    You can't say the current in the 12 V battery is 4 mA because the 3 K resistor is not the only load on the battery. I get 3.333 mA.

    The 1 mA is OK.
     
  4. Dec 7, 2011 #3
    Ya right
    I was confused
    Now I got it.
    Thank you :)
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Take a look at this simple circuit please.
  1. Simple Circuit (Replies: 1)

Loading...