1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Taking the square of a formula

  1. Aug 30, 2016 #1
    1. The problem statement, all variables and given/known data
    Hi sorry if the titel is wrong

    I want to know if i can write this

    ##a^2 + u^2 -2au= (a-u)^2 = (u-a)^2##
    I get different results when integrating ##x^{-\frac{3}{2}}## in the range ##(a-u)^2## to ##(a+u)^2##
     
  2. jcsd
  3. Aug 30, 2016 #2

    Mark44

    Staff: Mentor

    Yes, these expressions are all equal.
    It would be helpful to see your work.
     
  4. Aug 30, 2016 #3
    I've uploaded my work as images.
    Sorry for not using LaTex but im on mobile phone.
     

    Attached Files:

  5. Aug 30, 2016 #4

    Mark44

    Staff: Mentor

    I think the problem might be from taking the square root of (a - u)2. It's not necessarily equal to a - u. What is true is that ##\sqrt{(a - u)^2} = |a - u|## which in turn is equal to ##|u - a|##.
     
  6. Aug 31, 2016 #5
    Ok i got it.
    Thank you for your help
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Taking the square of a formula
  1. Is there a formula? (Replies: 2)

  2. Take the limit (Replies: 5)

Loading...