1. Limited time only! Sign up for a free 30min personal tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

I Tank outlet velocity exit pipe cross-section area dependence

  1. Mar 16, 2017 #1
    tank.png
    Sir, actually in a tank by the toricelli's law and also from bernoulli equation, we have outlet velocity as V= (2*g*H)^(1/2). In the case 2, I have closed the pipe exit partially with hand and observed a higher velocity than case 1, in practical. but when I applied the bernoulli equation at the surface of tank and pipe's outlet in the both cases, I am getting velocity V=(2*g*H)^(1/2) by energy conservation. But in practical the velocity is high in case 2.
    so, someone please solve me this, by considering the bernoulli energy equation at 1.the surface of tank and 2.at pipe exit
    Thank you
     
  2. jcsd
  3. Mar 16, 2017 #2

    Nidum

    User Avatar
    Science Advisor
    Gold Member

    The mean depth at the outlet is greater in case 2 than in case 1 .

    This should only make a noticeable difference though if the nominal mean depth is only equal to a small number of outlet pipe diameters .

    You don't say how you measured the velocity . Simple visual estimates of flow velocity can be very inaccurate and you may have just overestimated the difference in flow velocity for the two cases .
     
    Last edited: Mar 16, 2017
  4. Mar 30, 2017 #3
    Lets check both figures and lets forget for a while the pipes at the bottom of the tanks:

    Neglecting everything about fluid dynamics, and centering only on basic physics ...

    The fluid inside the tank will flow down at a speed of:

    V= sqrt(dens g h). If the surface area of the free surface is "S", the flowrate will be: Q= S x V


    Lets now have a look to the output pipe at the bottom, and lets assume, the height of the exit, in both cases to be the same.

    If the pipe section area is given by "A" and the output speed by "Ve", the output flowrate will be: Qo= Ve x A


    Continuity equation (and common sence) says that in "ideal" conditions, Flowrate at wich the tank level goes down, must be equal to the output flowrate, hence ...

    Q= Qo
    S x V= Ve x A

    Ve= V x S/A


    Meaning that ..... The less output section area "A", the higher output speed "Ve".


    The real world is not so "perfect". Fluids do not tend to behave so simply and many variables have to be taken into account.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook

Have something to add?
Draft saved Draft deleted



Similar Discussions: Tank outlet velocity exit pipe cross-section area dependence
Loading...