I Taylor Expansion Question about this Series

Click For Summary
The series presented is a Taylor expansion of the function f around the point x. It is expressed as f(x + α) and is a power series in α, indicating that the expansion is centered at x. Clarification is needed regarding the evaluation of derivatives, which should be explicitly calculated at the point x for better understanding. This will help in comprehending how the series approximates the function f near that point. The discussion emphasizes the importance of recognizing the center of the expansion in Taylor series.
LagrangeEuler
Messages
711
Reaction score
22
Can you please explain this series
f(x+\alpha)=\sum^{\infty}_{n=0}\frac{\alpha^n}{n!}\frac{d^nf}{dx^n}
I am confused. Around which point is this Taylor series?
 
Physics news on Phys.org
LagrangeEuler said:
Can you please explain this series
f(x+\alpha)=\sum^{\infty}_{n=0}\frac{\alpha^n}{n!}\frac{d^nf}{dx^n}
I am confused. Around which point is this Taylor series?

THis is an expansion about x. You can tell that because the series is a power series in \alpha.
 
It would help if the derivatives were explicitly evaluated at ##x##. Then it would be clearer.
 
Thread 'Problem with calculating projections of curl using rotation of contour'
Hello! I tried to calculate projections of curl using rotation of coordinate system but I encountered with following problem. Given: ##rot_xA=\frac{\partial A_z}{\partial y}-\frac{\partial A_y}{\partial z}=0## ##rot_yA=\frac{\partial A_x}{\partial z}-\frac{\partial A_z}{\partial x}=1## ##rot_zA=\frac{\partial A_y}{\partial x}-\frac{\partial A_x}{\partial y}=0## I rotated ##yz##-plane of this coordinate system by an angle ##45## degrees about ##x##-axis and used rotation matrix to...

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
6K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
19
Views
3K
  • · Replies 16 ·
Replies
16
Views
3K