Temperature and pressure gradient in a gas

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SUMMARY

The discussion centers on the relationship between temperature and pressure gradients in a gas within a tube, specifically one end maintained at 100°C and the other at 0°C. It is established that while a linear temperature gradient exists, the pressure remains constant throughout the tube. The molar density at any point along the tube is defined by the equation ##\frac{P}{RT(x)}##, leading to the conclusion that the total number of moles can be calculated using the integral $$n=\int_0^L{\frac{P}{RT(x)}Adx}$$. This analysis refutes the initial claim that a pressure gradient accompanies the temperature gradient.

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rejeev
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I have derived that, when there is a temperature difference (gradient) in a gas (consider a long tube with one end maintained at 100oC and other end maintained at 0oC), there will be a pressure gradient (something similar to Bernoulli's law).
Please see the attached document or this link for details: http://rejeev.blogspot.com/2010/07/pressure-and-temperature-gradient-in.html"
I would like to know the feedback from the community on this.
 

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rejeev said:
I have derived that, when there is a temperature difference (gradient) in a gas (consider a long tube with one end maintained at 100oC and other end maintained at 0oC), there will be a pressure gradient (something similar to Bernoulli's law).
Please see the attached document or this link for details: http://rejeev.blogspot.com/2010/07/pressure-and-temperature-gradient-in.html"
I would like to know the feedback from the community on this.
The analysis is incorrect. There will be a linear temperature gradient from A to B but the pressure will be constant. If the pressure is constant, the molar density at point x along the tube will be ##\frac{P}{RT(x)}##. So the total number of moles in the tube will be $$n=\int_0^L{\frac{P}{RT(x)}Adx}=\frac{PV}{R}\frac{1}{L}\int_0^L{\frac{dx}{T(x)}}$$ where A is the cross sectional area of the tube and V is the tube volume.
 

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