Tension in Rope using Torque? Did I do this correctly?

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kepherax
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Homework Statement
A wooden beam is suspended as shown below. The beam has a mass of 25 kg and has a length as shown. A sign is of mass 10 kg is to suspended from the beam at a distance of 2/3 from the edge of the beam. What is the tension in the rope?
Relevant Equations
Torque = |F||d|sin angle or r x F
Diagram of a wooden beam hinged to a wall on the left and held up by a rope from the wall at 37 degrees, with a sign reading Eat at Joe's hanging from the beam; the beam is labelled 15.0 m.


I think I understand but just want to check if I did this correctly, or if there is more to it...

Handwritten torque working for a beam on a pivot: a 10 kg mass hangs 10 m from the pivot, a 25 kg mass sits at the far end, and a rope tension T acts at 37 degrees, with torque sums written as Στ = 0 and T = 312.1 N circled.
 
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Where's the 'edge' of the beam ?
 
BvU said:
Where's the 'edge' of the beam ?

I set the pivot point to be where the beam meets the wall, the block on the left is the wall.