Tension of rope attached to basket

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SUMMARY

The problem involves two ropes of lengths 30cm and 40cm attached to a ceiling, spaced 50cm apart, supporting a 2kg basket. The solution requires applying static equilibrium principles, where the sum of forces in both the X and Y directions equals zero. The acceleration due to gravity is specified as 9.8 m/s². To find the tension in each rope, one must analyze the vector components of the forces acting on the basket.

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Homework Statement



Two lengths of rope, one 30cm long and the other 40cm long, are attached to a
ceiling at a distance of 50cm apart. The other ends of the rope are joined together
and attached to a basket weighing 2kg which hangs freely. Determine the tension in
each rope. (The acceleration due to gravity should be taken as g = 9.8m/s2.)

So it makes a triangular shape. The question needs to be done as an application of a vector but I was sick on the day it was covered in the lecture and never got to make up for it so I am not really sure were to go.

Homework Equations





The Attempt at a Solution

 

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this is a static problem. There is no acceleration. so the sum of Force in the Y and in the X direction should cancel eacher other out and equal zero. Go from there. What are the vectorial components of force? How can you relate that to your total net force?
 
Another important question, how do you find the height on this type of triangle. I think you should be able to figure it out.
 

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