Tension of Rope: Cosmonaut & Spaceship Orbit in Planetary Gravity

AI Thread Summary
The discussion centers on calculating the tension in a rope connecting a cosmonaut and a spaceship in orbit, with specific parameters provided. The gravitational attraction between the cosmonaut and the spaceship is calculated to be approximately 8.14 x 10^-9 N, but participants express uncertainty about the meaning of "negligible distance" in the problem statement. It is suggested that "negligible" likely refers to the orbital altitude above the planet's surface, impacting the analysis. Participants emphasize the importance of choosing an appropriate frame of reference and using free body diagrams for accurate calculations. The conversation highlights the need for clarity in problem statements to facilitate effective problem-solving.
Jorgen1224
Messages
36
Reaction score
0

Homework Statement


What is the tension of this rope?
Cosmonaut m=100kg is outside of spaceship M=5 tons on rope with length 64m. Cosmonaut along with his spaceship moves in orbit at a neglible distance.

m=100kg
M=5000kg
L=64m
Planet's mass 6*10^24
Planet's radius 6400km

Homework Equations


4ea196e90833059c9d91cd86bea05e3ec8b75d24

Kepler's 3rd law(maybe?)

The Attempt at a Solution



It's from physics olympics, so i bet that it requires one complex idea.
What comes out of universal gravitation law is 8.14208984375×10^-9 N and I'm not sure what to do afterwards.
 
Physics news on Phys.org
Is the statement of the problem exactly as it was given in the physics Olympics? I am not sure what "negligible distance" means. Negligible relative to the radius of the planet or negligible relative to 64 m?
 
  • Like
Likes Merlin3189
kuruman said:
Is the statement of the problem exactly as it was given in the physics Olympics? I am not sure what "negligible distance" means. Negligible relative to the radius of the planet or negligible relative to 64 m?
My guess is that the "negligible" refers to the orbital altitude above the planet's surface. The input data is good to one significant figure. So the use of reasonable approximations is apparently encouraged.

Perhaps the first order of business is to pick a frame of reference to use. An inertial frame nailed to the planet's center? A rotating frame nailed to the planet as a whole? Then the free body diagrams.
 
jbriggs444 said:
My guess is that the "negligible" refers to the orbital altitude above the planet's surface.
That would also be my guess, because otherwise the answer is trivial. However, I still would like to see the statement of the problem if it is different from the posted one.
 
  • Like
Likes jbriggs444
Jorgen1224 said:
Cosmonaut m=100kg is outside of spaceship M=5 tons
Jorgen1224 said:
M=5000kg
I'm still trying to parse this part...
 
Jorgen1224 said:
What comes out of universal gravitation law is 8.14208984375×10^-9 N
That is the gravitational attraction between the cosmonaut and the spacecraft based on their respective masses and separation. That could be important if we had a pole holding them apart. But in the case at hand we have a rope holding them together. What other force tends to separate the two?

[Note that it is easier to provide help when more of the work is shown and one does not have to reverse-engineer the result to figure out what went wrong]
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...

Similar threads

Back
Top