Tension rope and pulley problem

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SUMMARY

The tension rope and pulley problem involves two masses, each weighing 5 kg, connected by a rope over a pulley, with one mass on a 30-degree incline and the other hanging vertically. The correct formula for calculating the tension (T) in the rope is derived as T = (g * mass1 * mass2 * (1 + sin(theta))) / (mass1 + mass2), where g represents the acceleration due to gravity. The discussion emphasizes the application of gravitational force components and Newton's second law (F = ma) to solve for tension in this system.

PREREQUISITES
  • Understanding of Newton's second law (F = ma)
  • Basic knowledge of gravitational force and its components
  • Familiarity with trigonometric functions, specifically sine
  • Concept of tension in a rope system
NEXT STEPS
  • Study the derivation of tension in pulley systems with varying angles
  • Learn about the dynamics of connected masses in physics
  • Explore the role of friction on inclined planes in tension calculations
  • Investigate advanced problems involving multiple pulleys and masses
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Students studying physics, particularly those focusing on mechanics, as well as educators and tutors looking for examples of tension in pulley systems.

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Homework Statement



mass 1=mass 2= 5
theta=30

Mass 1 and mass 2 are connected by a rope on a pulley. Mass 1 is on an incline of 30 degrees, and mass 2 is hanging vertically. Find the tension of



The Attempt at a Solution



mgsin(theta)= force of gravity of mass 1 down the incline

mg= weight force of mass 2

mg+mgsin(theta)=Tension


The correct answer is (g(mass1)(mass2)(1+sin(theta)))/(mass1+mass2)

Can anyone please help me uderstand how to arrive at the correct answer?
 
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2. The only relevant equation I can think of F=ma
 

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