1. The problem statement, all variables and given/known data mass 1=mass 2= 5 theta=30 Mass 1 and mass 2 are connected by a rope on a pulley. Mass 1 is on an incline of 30 degrees, and mass 2 is hanging vertically. Find the tension of 3. The attempt at a solution mgsin(theta)= force of gravity of mass 1 down the incline mg= weight force of mass 2 mg+mgsin(theta)=Tension The correct answer is (g(mass1)(mass2)(1+sin(theta)))/(mass1+mass2) Can anyone please help me uderstand how to arrive at the correct answer?