Tensions in Suspended Ball System: Solving for Horizontal and Angled Cords

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The discussion focuses on calculating the tensions in a suspended ball system with a weight of 100-N. Participants clarify that since the ball is in equilibrium, the sum of forces must equal zero, leading to the conclusion that both the horizontal and vertical components of tension must balance the gravitational force. The tensions are denoted as T1 for the horizontal cord and T2 for the angled cord, with T2 needing to be resolved into its components. The importance of applying Newton's first law in both the x and y directions is emphasized to solve for the tensions. The original poster successfully resolves the problem after receiving guidance on these principles.
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Homework Statement



A ball weighing 100-N is shown suspended from a system of cords. What are the tensions in the horizontal and angled cords?

Homework Equations



F=ma

The Attempt at a Solution



I tried to use F=ma but I couldn't go anywhere with the equation. I know that sum of Forces (tension, gravity, normal?) equals the mass X acceleration, and there is no acceleration. So the forces equal the mass? And I got stuck here.
 

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Write down the forces acting on the ball and on the cords. Split the forces you get into x and y components.

You are correct in that F = ma. And there a is 0. So F = m*0 = 0. Sum of all forces should be 0 then.
 
Hi EndOfMemories, welcome to PF.
Let T1 be the tension in the horizontal cord and T2 be the tension in the angled cord.
Resolve T2 into vertical and horizontal components and apply the equilibrium conditions.
 
When an object is not in motion, there is no acceleration. Use Newton's first law in both the the y and x directions,where ax and ay are 0. . Note that tension forces always act in a direction pulling away from the object along the direction of the length of the cord, so there can be no vertical component of the tension in the horizontal cord.
 
Thanks guys I got it now
 
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