Tensor Algebras and Graded Algebras - Cooperstein - Theorem 10.11 and Defn 10.7

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SUMMARY

This discussion focuses on Bruce N. Cooperstein's "Advanced Linear Algebra (Second Edition)", specifically Section 10.3, which covers Tensor Algebras and Graded Algebras. Key points include the definition of the map \( S^k: V^k \longrightarrow \mathcal{A} \) and the nature of multiplication in the algebra \( \mathcal{A} \). The multiplication involved in the product \( S(v_1) S(v_2) \ldots S(v_k) \) is defined within the algebra \( \mathcal{A} \), adhering to the properties of an \( R \)-module and a ring. Additionally, the discussion clarifies that an algebra \( \mathcal{A} \) is \( \mathbb{Z} \)-graded if it consists of subspaces \( \mathcal{A}_k \) such that \( \mathcal{A}_k \mathcal{A}_l \subset \mathcal{A}_{k+l} \).

PREREQUISITES
  • Understanding of Tensor Algebras
  • Familiarity with Graded Algebras
  • Knowledge of algebraic structures such as \( R \)-modules and rings
  • Basic concepts of bilinearity in algebra
NEXT STEPS
  • Study the properties of Tensor Algebras in detail
  • Explore the implications of \( \mathbb{Z} \)-grading in algebraic structures
  • Learn about the dual nature of algebras as both \( R \)-modules and rings
  • Investigate examples of bilinear maps in algebra
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Mathematicians, algebraists, and students of advanced linear algebra seeking to deepen their understanding of tensor and graded algebras, particularly in the context of Cooperstein's work.

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I am reading Bruce N. Coopersteins book: Advanced Linear Algebra (Second Edition) ... ...

I am focused on Section 10.3 The Tensor Algebra ... ...

I need help in order to get an understanding of an aspect of Example 10.11 and Definition 10.7 in Section 10.3 ...

The relevant text in Cooperstein is as follows:View attachment 5565
View attachment 5566My questions related to the above text from Cooperstein are simple and related ... they are as follows:Question 1

In the above text from Cooperstein ... at the start of the proof of Theorem 10.11 we read the following:

" ... ... Define a map $$S^k \ : \ V^k \longrightarrow \mathcal{A}$$ by

$$S^k (v_1, \ ... \ ... \ , v_k ) = S(v_1) S(v_2) \ ... \ ... \ S(v_k)$$

... ... ... "


My question is ... what is the form and nature of the multiplication involved between the elements in the product $$S(v_1) S(v_2) \ ... \ ... \ S(v_k)$$ ... ... ?
Question 2

In the above text from Cooperstein in Definition 10.7 we read the following:

" ... ... An algebra $$\mathcal{A}$$ is said to be $$\mathbb{Z}$$-graded if it is the internal direct sum of subspaces $$\mathcal{A}_k , k \in \mathbb{Z}$$ such that

$$\mathcal{A}_k \mathcal{A}_l \subset \mathcal{A}_{k + l}$$

... ... ... "My question is ... what is the form and nature of the multiplication involved between the elements in the product $$\mathcal{A}_k \mathcal{A}_l$$ ... ... ?Hope someone can help ...

Peter
 
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Peter said:
I am reading Bruce N. Coopersteins book: Advanced Linear Algebra (Second Edition) ... ...

I am focused on Section 10.3 The Tensor Algebra ... ...

I need help in order to get an understanding of an aspect of Example 10.11 and Definition 10.7 in Section 10.3 ...

The relevant text in Cooperstein is as follows:
My questions related to the above text from Cooperstein are simple and related ... they are as follows:Question 1

In the above text from Cooperstein ... at the start of the proof of Theorem 10.11 we read the following:

" ... ... Define a map $$S^k \ : \ V^k \longrightarrow \mathcal{A}$$ by

$$S^k (v_1, \ ... \ ... \ , v_k ) = S(v_1) S(v_2) \ ... \ ... \ S(v_k)$$

... ... ... "


My question is ... what is the form and nature of the multiplication involved between the elements in the product $$S(v_1) S(v_2) \ ... \ ... \ S(v_k)$$ ... ... ?

It is the product in the algebra $\mathcal{A}$ (recall an algebra has a "dual nature" as both an $R$-module *and* a ring, such that the ring multiplication is *compatible* with the module addition, AND the ring-action of $R$-this is why we require $R$-bilinearity. In addition, we require that $R$ commute with $\mathcal{A}$-that is, that $R \subseteq Z(\mathcal{A})$, the center of $\mathcal{A}$).
Question 2

In the above text from Cooperstein in Definition 10.7 we read the following:

" ... ... An algebra $$\mathcal{A}$$ is said to be $$\mathbb{Z}$$-graded if it is the internal direct sum of subspaces $$\mathcal{A}_k , k \in \mathbb{Z}$$ such that

$$\mathcal{A}_k \mathcal{A}_l \subset \mathcal{A}_{k + l}$$

... ... ... "My question is ... what is the form and nature of the multiplication involved between the elements in the product $$\mathcal{A}_k \mathcal{A}_l$$ ... ... ?Hope someone can help ...

Peter

The set $\mathcal{A}_k\mathcal{A}_l = \{a \in \mathcal{A}: a = a_ka_l, a_k \in \mathcal{A}_k,a_l \in \mathcal{A}_l\}$ (it's just a "product set").
 
Deveno said:
It is the product in the algebra $\mathcal{A}$ (recall an algebra has a "dual nature" as both an $R$-module *and* a ring, such that the ring multiplication is *compatible* with the module addition, AND the ring-action of $R$-this is why we require $R$-bilinearity. In addition, we require that $R$ commute with $\mathcal{A}$-that is, that $R \subseteq Z(\mathcal{A})$, the center of $\mathcal{A}$).The set $\mathcal{A}_k\mathcal{A}_l = \{a \in \mathcal{A}: a = a_ka_l, a_k \in \mathcal{A}_k,a_l \in \mathcal{A}_l\}$ (it's just a "product set").
Thanks Deveno ... appreciate the clarification ... most helpful ...

Peter
 

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