Antarres
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I'm having a somewhat silly confusion, about interpretation of components of tensors in null basis(such as Newman-Penrose or similar formalisms).
For example, let's say that we're working in a 4d spacetime, and we have a null real orthonormal tetrad, consisting of null vectors ##k## and ##\ell##, and two spacelike vectors. The following relations(inner products) hold:
$$k \cdot k = 0 \qquad k \cdot \ell = 1 \qquad \ell \cdot \ell = 0$$
Now if we consider some tensor field on this manifold, let's say that it's a rank 2 covariant tensor field ##T_{ab}##. Then I am confused by the interpretation of the contraction ##T_{ab}k^a k^b##. I mean this in a sense that this contraction would usually be interpreted as a component of this tensor in the 'k-k' direction.
But for example, if I expand this tensor in the basis:
$$T_{ab} = A*k_a k_b + \dots$$
Then extracting this coefficient ##A##, we have ##A = T_{ab} \ell^a \ell^b##. But isn't this coefficient ##A## actually the component in 'k-k' direction? I'm pretty sure that my logic is mistaken somewhere.
In non-null case, the first interpretation would always be true, it seems natural, however, for some reason it confuses me since one could say that 'canonically' ##k_a## is dual to ##\ell^a##, while metrically, ##k_a## is obviously dual to ##k^a##.
It's important to rectify this, since in cases where these null vectors are used(for example in the analysis of null hypersurfaces), they usually have quite different physical meaning.
So which of these two interpretations is true?
For example, let's say that we're working in a 4d spacetime, and we have a null real orthonormal tetrad, consisting of null vectors ##k## and ##\ell##, and two spacelike vectors. The following relations(inner products) hold:
$$k \cdot k = 0 \qquad k \cdot \ell = 1 \qquad \ell \cdot \ell = 0$$
Now if we consider some tensor field on this manifold, let's say that it's a rank 2 covariant tensor field ##T_{ab}##. Then I am confused by the interpretation of the contraction ##T_{ab}k^a k^b##. I mean this in a sense that this contraction would usually be interpreted as a component of this tensor in the 'k-k' direction.
But for example, if I expand this tensor in the basis:
$$T_{ab} = A*k_a k_b + \dots$$
Then extracting this coefficient ##A##, we have ##A = T_{ab} \ell^a \ell^b##. But isn't this coefficient ##A## actually the component in 'k-k' direction? I'm pretty sure that my logic is mistaken somewhere.
In non-null case, the first interpretation would always be true, it seems natural, however, for some reason it confuses me since one could say that 'canonically' ##k_a## is dual to ##\ell^a##, while metrically, ##k_a## is obviously dual to ##k^a##.
It's important to rectify this, since in cases where these null vectors are used(for example in the analysis of null hypersurfaces), they usually have quite different physical meaning.
So which of these two interpretations is true?