Terminal speed and forces question

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To determine the terminal speed of a 72.0 kg skydiver modeled as a rectangular box, the drag force must equal the weight of the skydiver when at terminal velocity. The weight is calculated as 705.6 N. At terminal speed, the resultant force is zero, meaning the weight equals the drag force. By using the drag force formula, one can solve for the terminal velocity. This approach provides a clear method to find the skydiver's terminal speed when falling feet first.
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A 72.0 kg skydiver can be modeled as a rectangular "box" with dimensions 24.0 cm\times 47.0 cm\times 178 cm.

All I know is drag is a force so F=m*a or d=m*g which is 705.6N. After this I have no idea what to do. Any help?
 
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What is the question about? You are providing a set of values but what is it that the question
really wan?
 
Sorry:

What is his terminal speed if he falls feet first?
 
Clue to get u started.. If the person is at terminal speed, the resultant force will be equals to zero. Therefore, his weight - drag force will be equals to zero. Therefore, weight will be equal to drag force. Then by using the formula for drag force, you will be able to find the terminal velocity of the skydiver.
 
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