Terminal Velocity: Calculate Mass of 22cm Ball

AI Thread Summary
To calculate the mass of a 22cm diameter ball with a terminal velocity of 85m/s, the formula v^2 = (4mg)/A is used, but the area A should be calculated as A = pi r^2, not 4pi r^2. The radius is converted to 0.11m, leading to the correct area calculation. The discussion highlights a misunderstanding of the area needed for terminal velocity calculations, emphasizing the use of the largest cross-sectional area perpendicular to the direction of movement. The incorrect mass calculation of 28kg arises from this area miscalculation. Accurate application of the formulas is crucial for determining the correct mass.
StephenDoty
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v^2= (4mg)/A

so if a 22cm diameter ball has a terminal velocity of 85m/s, what would the mass of the ball be?
A = 4pi r^2
22cm= 0.22m
v^2 = (39.2m)/(4pi (.11)^2)
7225= (39.2m)/(pi*.0484)
So I got 28kg for the mass and that is not right. Please help.

Stephen Doty
 
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You have incorrectly noted that A=4pi r^2, where of course you meant A= pi r^2.
 
I know the area of a circle is pi r^2
but isn't the area of a sphere or a ball 4pi r^2 ?
 
In problems with air resistance we use area of the largest cross section of an object with a plane that is perpendicular to its direction of movement. In this case that is a circle with radius r
 
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