Terminal velocity of a coffee filter

AI Thread Summary
The discussion focuses on calculating the upward force of air resistance on a coffee filter and a stack of filters as they fall at terminal velocity. For a single coffee filter with a mass of 1.2 grams, the upward force of air resistance equals its weight, calculated using the equation Fair=mg. When dropping a stack of six filters, the same principle applies, with the upward force increasing proportionally to the total mass of the stack. The third part of the problem, estimating the time it takes for the stack to hit the ground, presents challenges due to insufficient information for applying the drag equation. The thread emphasizes the need for further exploration of the drag equation to solve this final part.
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Homework Statement



You drop a single coffee filter of mass 1.2 grams from a very tall building, and it takes 47 seconds to reach the ground. In a small fraction of that time the coffee filter reached terminal speed.

(a) What was the upward force of the air resistance while the coffee filter was falling at terminal speed?


(b) Next you drop a stack of 6 of these coffee filters. What was the upward force of the air resistance while this stack of coffee filter was falling at terminal speed?


(c) Again assuming again that the stack reaches terminal speed very quickly, about how long will the stack of coffee filters take to hit the ground?

Homework Equations



Fair=mg

The Attempt at a Solution



I got the first two parts by setting Fair=mg since these forces are equal in magnitude once terminal velocity is reached (zero net force) but I am seriously stumped on the third part. I thought about the drag equation but I don't see how it's possible to use that with the amount of information I have.
 
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