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[tex]\int \frac{x}{\left(x^2+z^2\right)^{3/2}} \, dx[/tex]

  1. Sep 13, 2009 #1
    1. The problem statement, all variables and given/known data
    [tex]\int \frac{1}{\left(x^2+z^2\right)^{3/2}} \, dx[/tex]

    I have been trying various u-substitutions for about 2 hours now, but I cannot seem to find a way to solve this by hand! I used mathematica to solve the problem. I feel like it will be fairly straightforward once I figure out what u should be, if u-sub is the way to go.

    This is for my electrodynamics course, and getting hung up on integrals is not helpful.

    I've tried:
    u=x^2
    u=1/(x2+z2)1/2
    u=1/(x2+z2)
    u=1/(x2+z2)3/2
    u=x/(x2+z2)1/2
    u=x/(x2+z2)
    u=(x2+z2)1/2
    u=(x2+z2)
    u=(x2+z2)3/2
     
  2. jcsd
  3. Sep 13, 2009 #2

    gabbagabbahey

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    Homework Helper
    Gold Member

    Have you tried a trig substitution....something like [itex]x=z\tan\theta[/itex] looks appropriate:wink:
     
  4. Sep 13, 2009 #3
    wow...never even crossed my mind to use trig substitution. In fact, I completely forgot that as a method. And its so useful! Thank you! I guess I ought to review calc 2 stuff from HS...

    Thanks again!
     
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