Teylor expantion of ln(1-e^-x)^-1

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In summary, the conversation is about finding the value of (ln(1-e^(-x))^(-1))^2 and simplifying it using Taylor's expansion and the multinomial theorem. The point being considered is x=0 and the exponent identity for logarithms (-1 inside ln is equivalent to -log(A)).
  • #1
zendani
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Dears
(ln(1-e^(-x))^(-1))^2=?
thankyou very much
http://www.uploadgeek.com/share-69EF_4A600E7F.html
 
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  • #2
Taylor's expansion about what point?
 
  • #3
and is the (-1) inside or outside the logarithm?
 
  • #4
(-1) is inside ln
ln((1-e^-x)^-1)
thank u
 
  • #5
Do, the taylor expansions, of ln(.), e^-x and (.)^-1separately, then compose (function composition) the results. Use the multinomial theorem to expand the terms in brackets. Then collect terms. As opposed to using the multinomial theorem you may be able to also use the fact that polynomial multiplication is the convolution of the coeficients. Have fun. It is going to be a mess. If you are skilled you may be able to write a computer algebra program which will give you each coefficient of the resulting polynomial.
 
  • #6
He still didn't answer "about what point"... x=0 is NOT a candidate.

Simplify what Johns said by using the exponent identity for logarithms.
log(A^(-1)) = -log(A)
 

What is the Teylor expansion of ln(1-e^-x)^-1?

The Teylor expansion of ln(1-e^-x)^-1 is a mathematical series that approximates the natural logarithm of the inverse of the function (1-e^-x). It is commonly used in calculus and other branches of mathematics.

How is the Teylor expansion of ln(1-e^-x)^-1 calculated?

The Teylor expansion is calculated by using the Teylor series, which is a formula for approximating a function using a polynomial. In this case, the Teylor series is used to approximate the natural logarithm of the inverse of (1-e^-x).

What is the significance of the Teylor expansion of ln(1-e^-x)^-1?

The Teylor expansion of ln(1-e^-x)^-1 is significant because it allows us to approximate complex functions with simpler ones. This can be useful for solving equations, making predictions, and understanding the behavior of a function.

What is the range of values for which the Teylor expansion of ln(1-e^-x)^-1 is valid?

The Teylor expansion is valid for values of x where (1-e^-x) is close to 0, which means that the function is close to its inverse. This typically occurs for values of x that are close to 0, as the inverse of (1-e^-x) is ln(1-e^-x). However, the accuracy of the approximation decreases as x gets further away from 0.

What are some real-world applications of the Teylor expansion of ln(1-e^-x)^-1?

The Teylor expansion has many real-world applications, including in physics, chemistry, and engineering. It is commonly used in the study of thermodynamics, quantum mechanics, and other fields that involve complex mathematical functions. It can also be used to approximate the behavior of financial systems and other real-world phenomena.

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