- #1

rdioface

- 11

- 0

## Homework Statement

Find the area of the lemniscate r

^{2}=6cos(2w) located to the right of the line r=3/2sec(w).

## Homework Equations

Area of a polar region is the integral from a to b (in this case a and b are where the curve intersects the line, I believe) of 1/2*r

^{2}d(w).

## The Attempt at a Solution

An attempt to find the points of intersection yield the equation 24/9*cos(2w)=sec

^{2}(w), which I have no idea how to solve. Additionally I'm not quite sure how to set up the integral in terms of what area minus what. I know it should be similar to the form for Cartesian int[a,b]f(x)dx-g(x)dx, but how am I to know which one is "lower" in terms of polar co-ordinates?