The Calculating $\cos\left({\sin^{-1}\left({2/3}\right)}\right)$

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Discussion Overview

The discussion revolves around calculating the value of $\cos\left({\sin^{-1}\left({2/3}\right)}\right)$, exploring the relationships between trigonometric functions, specifically sine, cosine, and tangent, in the context of inverse trigonometric functions. The scope includes mathematical reasoning and technical explanations related to trigonometric identities and their applications.

Discussion Character

  • Mathematical reasoning
  • Technical explanation

Main Points Raised

  • One participant states that $\tan\left({\arcsin\left({\frac{2}{3}}\right)}\right)=\frac{2\sqrt{5}}{5}$ but expresses confusion about this result.
  • Another participant explains that $\arcsin\left(\frac{2}{3}\right)$ corresponds to an angle in a right triangle with sides in the ratio of 2:3, leading to the calculation of the adjacent side as $\sqrt{5}$ and thus confirming that $\tan\left(\arcsin\left(\frac{2}{3}\right)\right)=\frac{2}{\sqrt{5}}=\frac{2\sqrt{5}}{5}$.
  • A different participant reiterates the confusion regarding the calculation of $\tan\left({\arcsin\left({\frac{2}{3}}\right)}\right)$ and suggests using the identity $\cos\left({\sin^{-1}\left({x}\right)}\right)=\sqrt{1-{x}^{2}}$ to find the cosine value.
  • One participant questions whether $\cos(x)$ would cancel out when using the suggested identity.
  • Another participant responds to the cancellation question, clarifying that the tangent formula does not lead to cancellation and provides a reformulation of the tangent in terms of sine and cosine.

Areas of Agreement / Disagreement

Participants express confusion and seek clarification on the calculations, indicating a lack of consensus on the understanding of the relationships between the trigonometric functions involved. Multiple viewpoints on the approach to the problem are present, and the discussion remains unresolved.

Contextual Notes

Participants rely on specific trigonometric identities and the properties of inverse functions, but there are indications of uncertainty regarding the application of these identities and the calculations involved.

karush
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$\tan\left({\arcsin\left({\frac{2}{3}}\right)}\right)=\frac{2\sqrt{5}}{5}$
Don't why this is the answer?
Supposed to use
$\cos\left({\sin^{-1}\left({x}\right)}\right)=\sqrt{1-{x}^{2}}$
 
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We know that $$\arcsin\left(\frac{2}{3}\right)$$ will be an angle in the first quadrant, and can be represented as an angle in a right triangle that has the ratio of the opposite to hypotenuse of 2:3. By the Pythagorean theorem, we then know the adjacent side is $\sqrt{5}$ units. And so the tangent of this angle is $$\frac{2}{\sqrt{5}}$$, and so we may state:

$$\tan\left(\arcsin\left(\frac{2}{3}\right)\right)=\frac{2}{\sqrt{5}}=\frac{2\sqrt{5}}{5}$$
 
karush said:
$\tan\left({\arcsin\left({\frac{2}{3}}\right)}\right)=\frac{2\sqrt{5}}{5}$
Don't why this is the answer?
Supposed to use
$\cos\left({\sin^{-1}\left({x}\right)}\right)=\sqrt{1-{x}^{2}}$
Well, you know how to calculate [math]cos(asn(2/3)) = \sqrt{1 - (2/3)^2}[/math]. Consider:
[math]tan \left ( asn \left ( \frac{2}{3} \right ) \right ) = \frac{sin \left ( asn \left ( \frac{2}{3} \right ) \right )}{cos \left ( asn \left ( \frac{2}{3} \right ) \right )}[/math]

You have just calculated [math]cos(asn(2/3))[/math]. All you need is [math]sin(asn(2/3))[/math]. How do you find this?

-Dan
 
Won't the $\cos(x)$ cancel out if we use the suggested identity?
 
karush said:
Won't the $\cos(x)$ cancel out if we use the suggested identity?
No. Using the hint the tan formula becomes:
[math]tan \left ( asn \left ( \frac{2}{3} \right ) \right ) = \frac{sin \left ( asn \left ( \frac{2}{3} \right ) \right )}{\sqrt{1 - \left ( \frac{2}{3} \right )^2}}[/math]

-Dan
 

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