x = 2cot t(adsbygoogle = window.adsbygoogle || []).push({});

y = (sin t)^2

t is greater than 0 but less than or equal to pi/2

The cartesian can be found using trig identities to be:

y = 8/ (4+ x^2)

What would be the range of the cartesian equation? I think it would be x is greater than or equal to 0, since when t = pi/2, x = 0, and as t tends to 0, x tends to infinity.

Am I correct?

Thank you.

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# Homework Help: The domain of a cartesian function from parametric equations

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