The Doppler Effect: Deducing an Expression for Frequency

Click For Summary

Homework Help Overview

The discussion revolves around the Doppler effect, specifically deducing an expression for the frequency perceived by a listener when a sound source moves at a constant velocity perpendicular to the listener's position. The original poster seeks to incorporate the distance L into their calculations.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to relate the frequency heard by the listener to the time variable and the distance L, questioning how to integrate L into their existing equations. Other participants suggest considering the velocity component of the source relative to the listener and how it affects the frequency calculation.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of the velocity component and its implications for the frequency equation. There is a focus on clarifying the relationship between the source's motion and the listener's position, but no consensus has been reached yet.

Contextual Notes

The original poster has provided a specific setup involving a sound source moving at a right angle to the listener, which may impose constraints on how the equations are applied. The discussion includes attempts to clarify the role of distance and velocity in the context of the Doppler effect.

jono90one
Messages
28
Reaction score
0

Homework Statement


A sound source moves at a constant velocity. A listener is standing at a distance L away from it. Given that the source moves in a straight line at a right angle to the listener and starts closest to the listener (ie at t=0) deduce an expression for the frequency heard by the listener in relation to time.

Homework Equations



fl=fs(v/(v-vs))
where l is listener and s is source

The Attempt at a Solution


It's obviously Doppler effect related.
So far I’ve done T=1/fs
And gotten
fl=v/T(v-vs)

But unsure how to get L into the equation.
Surely VT is the distance traveled by the wave and vsT is λs. Is there any orientation where L can be introduced? Or is this version correct?
 
Physics news on Phys.org
take in the velocity component of the source away from the observer at each instant of time in the governing equation.
 
(edit) So you mean f=v/T(vs-v)??
 
Last edited:
No
O(t=0)----------------------->vt(point A)(source)
|
|
|
|L
|
|
Point B(you)
I want you to find the component of source’s(A) velocity
Along the line joining point A & point B at an instant t
And plug that velocity into your equation for vs.
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
1K
Replies
8
Views
1K
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K