JesseM said:
What does "separable formalism" mean? You have a habit of not answering direct questions I ask you, which is frustrating. In my previous post I asked about the meaning of the similar phrase "parameter separability":
Can you please tell me if by "separable formalism" you just mean this idea that we can find local variables lambda in Alice's region that screen off the correlation between Alice's result with setting c and Bob's result with setting b, i.e. P(c+|b+, lambda) = P(c+|lambda)?
Not answering for ThomasT but just to chime in on what "parameter separability" means. Given an expression such as
ab + bc < ac
Separability allows me to rearrange the terms at will in the expression. I can factor out b on the LHS and treat each of the parameters as a standalone variable.
Note that this can not be done if our parameters are not communtative. In other words, if the value of a when it occurs together with b, is not the same as the value of a when it occurs with c, then we can not factor at will. The parameters will not be separable either, and therefore each term in the inequality (ie "ab", "bc", "ac") is a single indivisible whole which must be treated as such.
What has this got to do with Bell?
Bell derives his inequality by making use of the ability to factorize the terms at will. This introduces a separability requirement. If you are in doubt about this, see his derivation starting at equation 14. He introduces a P(a,c) term which he subtracts from a P(a,b) term, and by factorization and rearagement, he obtains a P(b,c) term. The fact that the P(b,c) term pops out from the P(a,b) and P(b,c) terms affirms this point.
What has this got to do with QM?
P(a,b) from QM does not commute with P(b,c), nor with P(a,c). So off the bat, we have a problem already before we can even do an QM calculations as those terms will not be compatible with Bell's inequality.
What about the experiments?
P(a,b) from one run of the experiment, does not commute with P(b,c) nor with P(a,c) from a different run of the experiment either. That is what QM has been telling us all along! For those whose concept of reality involves ridgit pre-existing properties which are passively revealed in Bell-type experiments it will be difficult to see how this is possible. All you need is for the parameters being measured to be contextual. Which simply means, a pre-existing property of the particles combines with a property of the device to reveal the outcome of an experiment.
Yet some may exclaim that if the value of 'a' in combination with 'b' is different from the value of 'a' in combination with 'c', it means there is spooking action between "setting a" and "setting b". That is certainly the naive interpretation since all that is required is for the process which produces the particle pairs to be non-stationary (
http://en.wikipedia.org/wiki/Stationary_process)
Therefore Bell's theorem is mistated in my opinion. It will be better stated as:
Non-commuting expectation values are not compatible with Bell's inequalities
Or
Non-separable expectation values are not compatible with Bell's inequalities
Or
You can not eat your cake and have it
Which would have been stating the obvious if not of all the noise surrounding Bell's theorem.