Chemistry The electrical work needed to produce a mole of lead in a chemical reaction

[rafehi]

Homework Statement

Consider the charging of a lead-acid batter at atmospheric pressure and room room temperature.

2PbSO₄ +2H₂O -> Pb + PbO₂ + 4H⁺ + 2SO₄^2-

How much electrical work must be provided to produce one mole of lead?

The Attempt at a Solution

We're given the values of Gibbs Free Energy and Enthalpy for each of the reactants.

I was doing a past paper for a uni exam and I came across that question. Now correct me if I'm wrong but isn't the electric work equal to the \DeltaG?

So W_elec = G_final - G_initial?

I'm fairly sure that's the case but the answer shows it calculated as
W = H_final - H_initial

Again, correct me if I'm wrong but wouldn't that give compression/expansion work?

 

[vertciel]

Hello there,

I am unsure about how your solution addressed this question, but this is what I would do.

1) You need to understand this equation: ∆G = nFE⁰_cell.

2) You can calculate ∆G for the entire reaction using tabulated values of ∆G for each reactant. That is, ∆G for the reaction = ∆G products - ∆G reactants.

3) The chemical equation is in fact a redox equation. Find the number of electrons transferred in that equation to determine the value of n for the above equation.

4) Now that you know ∆G, n, and F (This is Faraday's constant, which can be found online or in your textbook), you can find E⁰_cell by rearranging the above equation.

I hope that this helps! Feel free to write back!

 

[rafehi]

Thanks for the reply.

Not sure why my topic was moved here though because the question came up in a Thermal Physics course, so we're not particularly interested in electron transfer or what have you.

We were given the values of Gibbs Free Energy and Enthalpy - the change was easily calculated. My question was more a conceptual one - namely, what exactly a change in the Gibbs Free Energy means physically. I'm now confident that it is the change in electrical work (or any work that isn't compression/expansion) and that the solution to the exam must have been incorrect.

 

[vertciel]

Hello there,

Unfortunately, I'm not an expert in the area of thermal physics. I have always interpreted Gibbs Free Energy as the amount of energy available to do work in a system.

Does that help?