The End of the Universe in an Instant

  • Thread starter Thread starter JDude13
  • Start date Start date
  • Tags Tags
    Universe
JDude13
Messages
95
Reaction score
0
A distant observer watches you take an infinite amount of time to reach the event horizon. From your perspective you reach the event horizon after a finite amount of time.
Would it be fair to say that, upon reaching the event horizon you will have seen the rest of the universe's existence in its entireity?
 
Physics news on Phys.org
No, if you _fall _ into a black hole, you won't see the end of the universe. I've posted some references on this in the past, I'm sure you can find them if you look.

You could see the end of the universe - well, an arbitrary but finite amount of time into the future - if you use rockets to hover just above the event horizon of a black hole. But with the same rocketship, you could see the end of the universe by just flying around and taking advantage of time dilation.
 
ud die before youd see the end of the universe becouse of spaghetification
 
nickthrop101 said:
ud die before youd see the end of the universe becouse of spaghetification

For supermassive black holes, you can pass through the event horizon without being subjected to tidal forces big enough to kill you.
 
I started reading a National Geographic article related to the Big Bang. It starts these statements: Gazing up at the stars at night, it’s easy to imagine that space goes on forever. But cosmologists know that the universe actually has limits. First, their best models indicate that space and time had a beginning, a subatomic point called a singularity. This point of intense heat and density rapidly ballooned outward. My first reaction was that this is a layman's approximation to...
Thread 'Dirac's integral for the energy-momentum of the gravitational field'
See Dirac's brief treatment of the energy-momentum pseudo-tensor in the attached picture. Dirac is presumably integrating eq. (31.2) over the 4D "hypercylinder" defined by ##T_1 \le x^0 \le T_2## and ##\mathbf{|x|} \le R##, where ##R## is sufficiently large to include all the matter-energy fields in the system. Then \begin{align} 0 &= \int_V \left[ ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g}\, \right]_{,\nu} d^4 x = \int_{\partial V} ({t_\mu}^\nu + T_\mu^\nu)\sqrt{-g} \, dS_\nu \nonumber\\ &= \left(...
In Philippe G. Ciarlet's book 'An introduction to differential geometry', He gives the integrability conditions of the differential equations like this: $$ \partial_{i} F_{lj}=L^p_{ij} F_{lp},\,\,\,F_{ij}(x_0)=F^0_{ij}. $$ The integrability conditions for the existence of a global solution ##F_{lj}## is: $$ R^i_{jkl}\equiv\partial_k L^i_{jl}-\partial_l L^i_{jk}+L^h_{jl} L^i_{hk}-L^h_{jk} L^i_{hl}=0 $$ Then from the equation: $$\nabla_b e_a= \Gamma^c_{ab} e_c$$ Using cartesian basis ## e_I...
Back
Top