The field just outside a metal ball

AI Thread Summary
The electric field just outside a 3.22 cm radius metal ball is measured at 2.72×10^2 N/C, directed toward the ball. Using the equation E = k*q/r^2, the calculated charge on the ball is approximately 3.14×10^-11 C. However, the field's direction indicates that the charge is negative, as it points toward the ball. This aligns with Gauss's law, which supports the conclusion of a negative charge. Therefore, the correct interpretation of the charge is essential for accurate problem-solving.
Hooke's Law
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Homework Statement



The field just outside a 3.22 cm radius metal ball is 2.72×10^2N/C and points toward the ball. What charge resides on the ball?

Homework Equations



E = k*q/r^2



The Attempt at a Solution



q = E*r^2/k

q = ( 2.72*10^2 N/C )* (0.0322 m^2) / 8.99*10^9

= 3.14*10^-11 C


The computer says I'm giving it the wrong answer...is there something wrong with what I did?


Thanks
 
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The magnitude of your answer seems correct...thats what Gauss's law gives ...
but i think the charge is negative because the field is pointing towards the ball...try it...
 
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